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Makovka662 [10]
3 years ago
7

Simpliy completely 4m^3/3m^2n * 9n^2/30m^2n^2

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
6 0
Hey there!

(KEY POINT HERE) 

\searrow\searrow\searrow\searrow\searrow\searrow\searrow\searrow\searrow\searrow \ \swarrow\swarrow\swarrow\swarrow\swarrow\swarrow\swarrow\swarrow\swarrow \\ \\  \boxed{(((((4* \frac{(M^3)}{3} *(m^2))*n)*9)* \frac{n^2}{30} *m^2)*n^2}

Now that we have considered that equation above, we would now understand what is clear to be your (correct answer).

Your correct answer to this question listed above would be (option B).

\boxed{\boxed{2 m / 5 n}}

I hope this helps you!
Semenov [28]3 years ago
5 0
The answer is 2/5mn

see attached picture for steps:

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Please help and show work so I can understand how too alive this question please
nataly862011 [7]

Answer:

she has 24 shoes

Step-by-step explanation:

12 x 2(pair)=24

8 0
3 years ago
Use decimals and fractions in the same equation showing the Commutative Property. Repeat for the Associative Property.
Anna71 [15]

For Commutative Property of Addition

Let us take a decimal number 2.14 and a fraction \frac{5}{20}

Now, according to the Commutative property of Addition:

For any two numbers a and b :

a+b = b+a

So, for 2.14 and \frac{5}{20}

Let us add

2.14+\frac{5}{20}  = \frac{214}{100}  +\frac{5}{20}

                                   =\frac{214}{100}  + \frac{5 \times 5}{20 \times 5} \\ \\=\frac{214}{100}  + \frac{25}{100} \\ \\= 2.14 + 0.25 \\ \\ = 2.39

Also,

\frac{5}{20} + 2.14  = \frac{5}{20} + \frac{214}{100}

                                     = \frac{5 \times 5}{20 \times 5} +\frac{214}{100} \\ \\= \frac{25}{100}  + \frac{214}{100} \\ \\=  0.25 + 2.14 \\ \\ = 2.39

Therefore, 2.14+\frac{5}{20} = \frac{5}{20} + 2.14

Hence,  Commutative Property of Addition is satisfied.


For Associated Property of Addition

Let us take two same decimal numbers 2.14 , 7.25 and a fraction \frac{5}{20}

Now, according to the Associated property of Addition:

For any three numbers a, b  and  c

a + (b+c) =(a+b) + c

So, for 2.14 , 7.25 and \frac{5}{20}

The Left hand side:

a + (b+c)

2.14 + (7.25 + \frac{5}{20}) = 2.14 + (\frac{725}{100} + \frac{5 \times 5}{20\times 5})

                                                         = 2.14 + (\frac{725}{100} + \frac{25 }{100})

                                                         = 2.14 + (\frac{750}{100} )

                                                        = \frac{214}{100} + \frac{750}{100}

                                                         = \frac{964}{100}

                                                        =9.64


The Right hand side:

(a + b )+c

(2.14 + 7.25 )+ \frac{5}{20}= ( 9.39 ) + \frac{5 }{20}

                                                = 9.39  + \frac{5 \times 5 }{20 \times 5}

                                                = 9.39  + \frac{25}{100}

                                                = 9.39  + 0.25

                                                = 9.64


Thus,

(2.14 + (7.25 + \frac{5}{20} )= (2.14 + 7.25 )+ \frac{5}{20}

Therefore, 2.14+\frac{5}{20} = \frac{5}{20} + 2.14

Hence,  Associative Property of Addition is satisfied.




8 0
3 years ago
In a small town, the use of coal (W in tons/per
zimovet [89]

Answer:

i)W = 2500 / T

ii)  W = 500 Tons

iii) grad W(10°) = - 25î

iv) The formulation is not practical

Step-by-step explanation:

i)  Write an equation describing the use of coal

As use of coal is inversely proportional to the average monthly temperature

if  W is use of coal in tons/per month then

W(t)  =   k / T              where k is a constant of proportionality and T is the average temperature in degrees. We have to determine k from given conditions

k  =  ??   we know that when   T  =  25°    W = 100 tons  the by subtitution

W = k/T           100  =  k /25       k  =  2500 Tons*degree

Then final equation is:

W = 2500 / T

ii) Find the amount of coal when T = 5 degrees

W = 2500 / 5

W = 500 Tons

iii)

The inverse proportionality implies that W will decrease as T increase.

The vector gradient of W function is:

grad W  = DW(t)/dt î  

grad W  = - 2500/T² î

Wich agrees with the fact that W is decreasing.

And when T = 100°

grad W(10°) =  - 2500/ 100 î      ⇒  grad W(10°) = - 25î

iv) When T =  0  The quantity of coal tends to infinite and the previous formulation is not practical

5 0
3 years ago
Pls help me with this question it wold be great help its circumference
Ivan

Answer:

C = 9.42\ m

Step-by-step explanation:

The formula for the circumference of a circle with the diameter is:

C = \pi d

Since the diameter is 3m, solve for C:

C = \pi d\\C = \pi3\\C = (3.14) \times 3\\C = 9.42

6 0
2 years ago
Read 2 more answers
I want to know how to solve this.
Anton [14]

Answer:

C

Step-by-step explanation:

Hope this helps

let me know if I’m wrong

5 0
3 years ago
Read 2 more answers
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