Answer:
master file contains data types while transaction file is used to record Master file
Explanation:
hope it helps
a. speed + 12 - miles * 2 = 10 + 12 - 5 * 2. With order of operations, we do the multiplication first so the equation is now 10 + 12 - 10 = 22 - 10 = 12
b. speed + miles * 3 = 10 + 5 * 3 and again, order of operations gives us 10 + 15 = 25
c. (speed + miles) * 3 = (10 + 5) * 3 = 15 * 3 = 45
d. speed + speed * miles + miles = 10 + 10 * 5 + 5 = 10 + 50 + 5 = 60 + 5 = 65
e. (10 – speed) + miles / miles = (10 - 10) + 5 / 5 = 0 + 5 / 5 = 5 / 5 = 1
Answer:
The function definition to this question can be given as:
Function definition:
void printAttitude(int x1) //define function printAttitude.
{
//nested else-if statements
if(x1==1)
//if block
cout<<"disagree"<<endl;
//message
else if(x1==2)
//else if block
cout<<"no opinion"<<endl;
//message
else if(x1==3)
//else if block
cout<<"agree"<<endl;
//message
else
cout<<" ";
}
Explanation:
In the above method definition firstly, we define a method that is "printAttitude". In this method, we pass an integer variable that is "x1". This function does not return any value because its return type is void. In this method, we use nested else-if statements. The description of these conditions can be given as:
- In the if block we check the variable x1 value is equal to 1 If this condition is true. It will print "disagree" otherwise it will go to else-if block.
- In the else-if block, we check the variable x1 value is equal to 2 if the condition is true. It will print "no opinion". otherwise, we will go to another else-if block.
- In this block, we check the variable x1 value is equal to 3 if this condition is true. It will print "agree".otherwise it will go to else block.
- In the else block it will print nothing.
Answer:
Explanation:
We have the following
t is the number of test cases.
n is the number of trips for each testcase
name is the name of the city
all the unique names are added to the list and at last the length of the list is printed.
The program is written as follows
t = int(input) - for i in range(t): n = int(input) 1 = [] for j in range(n): name = input if name not in l: 1.append(name) pr
t = int(input())
for i in range(t):
n = int(input())
l = []
for j in range(n):
name = input()
if name not in l:
l.append(name)
print(len(l))
Output:
<span>a distributed application structure that partitions tasks or workloads between the providers of a resource or service, called servers, and service requester, called clients</span>
