Answer: mathematical modelling helps to look into the uncertainties in the calculations based on the observational data.
Explanation:
In bioinformatics for example in gene data expression there can millions of data obtained through various observatory experiments. however most of the data is inadequate to arrive at at a conclusion. So in order to solve this issue we have to apply mathematical modelling to consider those data which would help us to understand the models behavior and access its performance.
With CIDR (Common Internet Domain Routing), the first decimal number isn't important any more. The /24 netmask means that there's one octet (256) numbers that aren't part of the network number. The .0 address is the network number itself and .255 is the broadcast address of the network, so that leaves 254 available node numbers, but one of those has to be a router or else the machines can't communicate with other networks.
Answer:
// Producer Thread
void *producer(void *param) {
buffer_item item;
while (true) {
item = rand() % 100;
sem_wait(&empty);
pthread_mutex_lock(&mutex);
if (insert_item(item))
printf("Can't insert item\n");
else
printf("Producer %d: produced %d\n", *((int*)param), item);
pthread_mutex_unlock(&mutex);
sem_post(&full);
}
}
// Consumer Thread
void *consumer(void *param) {
while (true) {
buffer_item item = NULL;
if (in > 0)
item = buffer[in - 1];
sem_wait(&full);
pthread_mutex_lock(&mutex);
if (remove_item(&item))
printf("Can't remove item\n");
else
printf("Consumer %d: consumed %d\n", *((int*)param), item);
pthread_mutex_unlock(&mutex);
sem_post(&empty);
}
}
Explanation:
An outline of the producer and consumer threads appears as shown above.
Answer:
Option(a) i.e "true" is the correct answer for the given question.
Explanation:
The select statement is used for fetching the record in the database. Select is the Data manipulation command. The given query gives all the records where id=5 from the table publisher in the table format.After executing of query the user can verify that the field is updated or not in the table.
So the given statement is "true".
Answer:
O(N!), O(2N), O(N2), O(N), O(logN)
Explanation:
N! grows faster than any exponential functions, leave alone polynomials and logarithm. so O( N! ) would be slowest.
2^N would be bigger than N². Any exponential functions are slower than polynomial. So O( 2^N ) is next slowest.
Rest of them should be easier.
N² is slower than N and N is slower than logN as you can check in a graphing calculator.
NOTE: It is just nitpick but big-Oh is not necessary about speed / running time ( many programmers treat it like that anyway ) but rather how the time taken for an algorithm increase as the size of the input increases. Subtle difference.
