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3 years ago

In this illustration, which group highlights, or which groups highlight, nonmetals?

Chemistry

2 answers:

vesna_86 [32]3 years ago

6 0

Answer:

Groups B and D

Explanation:

The attached picture is that of the periodic table of elements. There are four colours showing different classes of the elements. The colours are coded A,B,C and D

A are metals (alkali metals, alkali earth metals, transition metals, actinides and lanthanides)

B and D are non-metals (halogens and gases including noble gases)

C are metalloids or semi-metals (they have some properties similar to metals and non-metals)

B and D is the answer because elements found in those colours have properties different from that of metals

Step2247 [10]3 years ago

5 0

Answer:

I'm pretty sure it's B and D

Explanation:

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Find the mass in grams of 2.65 x 10^24 molecules of cl2

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= 70.906 x 4.4
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Hope this helps!

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4 years ago

Both the freezing temperature and the melting temperature of water are the same(0°C). Explain why a substance like water freezes

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4 years ago

What mass of magnesium hydroxide is required to create a 441 mL solution with a pH of 12.52?

marshall27 [118]

Answer:

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Explanation:

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4 0

3 years ago

one bottle of aspirin holds 250 tablets, each containing 150 mg of aspirin and sells for $2.95. Another bottle holds 125 tablets

AlladinOne [14]

I bottle:

250 * 150mg = 37500mg

If 37500mg ------- cost ------- $2.95
so 1mg ------- cost ------- x

x = 1mg* $2.95 / 37500mg = $7,87*10⁻⁵

II bottle

125 * 200mg = 25000mg

If 25000mg ---------- cost ---------- $3.50
so 1mg ---------- cost ---------- x

x = 1mg* $3.50 / 25000mg = $0,00014=$1,4*10⁻⁴

$7,87*10⁻⁵ < $1,4*10⁻⁴

1st bottle is better bargain cause 1mg of aspirin its cheaper than in 2nd.

7 0

3 years ago

Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following

bearhunter [10]

Answer:

$210.7~g~MgCO_3$

Explanation:

We have to start with the reaction:

$MgCO_3~->~MgO~+~CO_2$

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the number of moles that we have in the 110.0 g of carbon dioxide, to this, we have to know the atomic mass of each atom:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the molar mass of carbon dioxide:

$(12*1)+(16*2)=44~g/mol$

In other words: $1~mol~CO_2=~44~g~CO_2$ . With this in mind, we can calculate the moles:

$110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2$

Now, the molar ratio between carbon dioxide and magnesium carbonate is 1:1, so:

$2.5~mol~CO_2=2.5~mol~MgCO_3$

With the molar mass of $MgCO_3$ ( $(23.3*1)+(12*1)+(16*3)=84.3~g/mol$ . With this in mind, we can calculate the grams of magnesium carbonate:

$2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3$

I hope it helps!

8 0

3 years ago