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a_sh-v [17]
3 years ago
6

Why do they compare the building of a city to that of a human body?

Chemistry
1 answer:
taurus [48]3 years ago
5 0

Answer:

Human body systems can be compared to anything that has many parts doing specialized jobs to help the whole. Here's an example: The human body is like a city. The nervous system of the body is like the government of the city because the nervous system controls the body like the government controls the city.

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If you have a graduated cylinder, containing 15.5 mL and this volume changes to 95.2 mL after a metal with a mass of 7.95g is dr
xxTIMURxx [149]

Answer: The density of the object will be 9.97\times 10^{-2} g/ml.

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of object = 7.95 grams

Volume of water displaced = volume of the object = (95.2 - 15.5) ml =79.7 ml

Putting in the values we get:

Density=\frac{7.95g}{79.7ml}=0.0997g/ml

Thus density of the object will be 9.97\times 10^{-2} g/ml

4 0
4 years ago
How many total electrons can be contained in the 4d sublevel? <br> 2<br> 6<br> 10<br> 14
qaws [65]
<span>The s sublevel has just one orbital, so can contain 2 electrons max. The p sublevel has 3 orbitals, so can contain 6 electrons max. The d sublevel has 5 orbitals, so can contain 10 electrons max. And the 4 sublevel has 7 orbitals, so can contain 14 electrons max.
So, having this in mind, 10 electrons in total can be contained in the 4d sublevel.
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5 0
4 years ago
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Is there any one who can help me in chemistry?
BaLLatris [955]
I can try.
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4 0
3 years ago
Periods on the periodic table represent elements_____.
AlekseyPX
A period in the periodic table is a row of chemical elements. All elements in a row have the same number of electron shells
8 0
3 years ago
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Need help on #129. Please help!
MrRissso [65]

The percentage yield is 72.8 %.

<em>Step 1</em>. Calculate the <em>mass of Br₂</em>

Mass of Br₂ = 20.0 mL Br₂ × (3.10 g Br₂/1 mL Br₂) = 62.00 g Br₂

<em>Step 2</em>. Calculate the <em>theoretical yield</em>

M_r:           159.81    266.69

         2Al + 3Br₂ → 2AlBr₃

Moles of Br₂ = 62.00 g Br₂ × (1 mol Br₂/(159.81 g Br₂) = 0.3880 mol Br₂

Moles of AlBr₃ = 0.3880 mol Br₂ × (2 mol AlBr₃/(3 mol Br₂) =  0.2586 mol AlBr₃

Theor. yield of AlBr₃ = 0.2586 mol AlBr₃ × 266.99 g AlBr₃)/(1 mol AlBr₃)

= 69.05 g AlCl₃

<em>Step 3</em>. Calculate the <em>percentage yield </em>

% yield = (actual yield/theoretical yield) × 100 % = (50.3 g/69.05 g) × 100 %

= 72.8 %

5 0
3 years ago
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