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sasho [114]
2 years ago
12

Which model was proposed as a result of Rutherford's scattering experiment where positive particles did not pass straight throug

h a foil as expected?

Chemistry
1 answer:
dimulka [17.4K]2 years ago
6 0

Answer:

the nuclear model of the atom

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Which of the following substances is most likely to be a liquid at room temperature?
nikitadnepr [17]

Answer:

The correct answer is d.hydrogen peroxide H₂O₂H₂O₂

Explanation:

Substances can be found in nature in different <em>aggregation states. </em>

Agreggation states can be liquid, gas or solid.

The problem asks about which substance can be found in room temperature as <em>liquid.</em> Each subtances has different physical and chemical properties that determines in which state you can find them at room temperature.

Hydrogen peroxide is the only substance listed that is in liquid state at room temperature, all other substances are in gas state at room temperature.

3 0
3 years ago
What gas law states that pressure and temperature are directly proportional at
Rus_ich [418]
Charles Law is the law that states pressure and temperature are directly proportional at constant volume and miles
8 0
3 years ago
Read 2 more answers
Alkanes are chains of carbon atoms surrounded by hydrogen atoms. <br><br> a. True<br> b. False
Ne4ueva [31]

Answer:

a. True

Explanation:

Alkanes are chains of carbon atoms surrounded by hydrogen atoms. TRUE.

Alkanes are hydrocarbons, that is, they are organic compounds formed only by carbon and hydrogen. In alkanes, carbon atoms are bonded to each other through single covalent bonds and they are also bonded to hydrogen atoms through the same type of bonds. Alkanes have the general formula CnH2n+2.

7 0
3 years ago
The RNA and DNA backbone differ because the DNA sugar is missing what element?
hammer [34]

Answer:

D.

Explanation:

4 0
2 years ago
One gram of liquid benzene is burned in a bomb calorimeter. The temperature before ignition was 20.826 C, and the temperature af
Licemer1 [7]

Answer:

fH = - 3,255.7 kJ/mol

Explanation:

Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.

Qsystem + Qcombustion = 0

Qsystem = heat capacity*ΔT

10000*(25.000 - 20.826) + Qc = 0

Qcombustion = - 41,740 J = - 41.74 kJ

So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:

n = mass/molar mass = 1/ 78

n = 0.01282 mol

fH = -41.74/0.01282

fH = - 3,255.7 kJ/mol

4 0
4 years ago
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