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DIA [1.3K]
3 years ago
8

What is the equation of a line that is parallel to the line x=-2and passes through the point (-5, 4)?

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
6 0
First, it is important to understand that any equation that is x=some number is just a vertical line that hits the x-axis at the given number. For example, x=-2 would be a vertical line hitting the x-axis at -2. Therefore, the line we are trying to identify would also be vertical (and have the form x=some number) because we know the lines are parallel. Then, since we're given the point (-5,4), we know the line needs to hit the x-axis at -5, therefore the equation would be x=-5.

I hope this helps.
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Decompose fraction 2 3/4
ludmilkaskok [199]

Answer:

11 * 1/4

Step-by-step explanation:

Hi!

Since to decompose a fraction means to basically take it apart, that's all we have to do!

Breaking down the fraction, we can see that it is composed of a bunch of 1/4.

(As an improper fraction below.)

\frac{11}{4}.

That's just 11 \cdot \frac{1}{4}.

Thus, the answer is \boxed{11\:\cdot\:\frac{1}{4}}.

Hope this helps!

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2 years ago
What is the solution to the equation 1 over the square root of 8 = 4(m + 3)?
AnnyKZ [126]
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3 0
2 years ago
If f(x) = kx^3+ x^2 − kx + 2, find a number k such that the graph of f contains the point (k, -10)
Elina [12.6K]

If we write k where we see x in the equation and set the result equal to -10, we get the result.

  • f(k)=k(k)^3+k^2-k(k)+2
  • =k^4+k^2-k^2+2
  • =k^4+2=-10
  • k^4=-12
  • k_{1}=\sqrt[4]{3}(-1-i)
  • k_{2}=\sqrt[4]{3}(-1+i)
  • k_{3}=\sqrt[4]{3}(1-i)
  • k_{4}=\sqrt[4]{3}(1+i)

4 0
11 months ago
Whats the area of this parallelogram?
mart [117]
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A= 6cm + 5cm
A= 11cm
A= 11cm x 12cm
A= 132cm

So your answer is 132cm.
7 0
3 years ago
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