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mel-nik [20]
3 years ago
13

108/40 in its simplest form

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
5 0

Answer:

  27/10

Step-by-step explanation:

A calculator can tell you the fraction value is 2.7. As the ratio of integers, this is ...

  108/40 = 27/10

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The domain of the function f(x)=3x-6/x is {-3, -1, 2, 4, 5}. What is the function's range?
Maslowich
<span> f(x)=[3x-6]/x is {-3, -1, 2, 4, 5}

</span> f(-3)=[3(-3) -6]]/-3 = -15/-3 = 5
 f(-1)=[3(-1) -6]]/-1= -9/-1 = 9
 f(2)=[3(2) -6]]/2 = 0/2 = 0
 f(4)=[3(4) -6]]/4 = 6/4 = 1.5
 f(5)=[3(5) -6]]/5 = 9/5 = 1.8
<span>
answer is 

</span><span>c {5, 9, 0, 1.5, 1.8} </span>
3 0
3 years ago
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Answer me pleaseeee. What is 3*3*3*3*3*3*3*3*8*8*0*8*8*9*8*6? Gk test​
olchik [2.2K]

Answer:

0

Step-by-step explanation:

Since we're multiplying by 0, the entire product becomes 0.

6 0
2 years ago
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Help please I don't remember ​
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Answer: G would be at (1,0)

F (-1,3)

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3 0
2 years ago
The sum of x and it’s opposite is always zero?
jeka94

Answer:

1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies

2) Now let's consider any real number a no matter positive or negative we will have that:

a-a =0

Or in the other case:

-a -(-a) =-a +a=0

So then we can conclude that the expression is a general rule and is true

Step-by-step explanation:

For this case we can verify if the following expression is true or false:

The sum of x and it’s opposite is always zero?

If we want to proof this we need to show that for any number is true.

1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies

2) Now let's consider any real number a no matter positive or negative we will have that:

a-a =0

Or in the other case:

-a -(-a) =-a +a=0

So then we can conclude that the expression is a general rule and is true

5 0
3 years ago
H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?
zubka84 [21]
H(x)=(x^2)+1\ \ \ \ and\ \ \ \  K(x)=-(x^2)+4. \\\\K(H)=-(H^2)+4=-(x^2+1)^2+4=4-(x^2+1)^2=\\\\.\ \ \ =2^2-(x^2+1)^2=(2-x^2-1)(2+x^2+1)=(1-x^2)(3+x^2)=\\\\.\ \ \ =(1-x)(1+x)(x^2-3\cdot i^2)=(1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)\\\\ K(H)=0\ \ \ \ \Leftrightarrow\ \ \ (1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)=0\\\\x=1\ \ \ \ or\ \ \ \ x=-1\ \ \ \ or\ \ \ \ x=\sqrt{3} \cdot i\ \ \ \ or\ \ \ \ x=-\sqrt{3} \cdot i\\\\Ans.\ e.
4 0
2 years ago
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