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zlopas [31]
3 years ago
6

IF ONE THIRD OF THE SCHOOL STUDENTS LIKE MATHEMATICS AND 400 STUDENTS DO NOT LIKE MATHEMATICS , THEN HOW MANY STUDENTS DOES THE

SCHOOL HAVE ?
A. 600 B. 800
C. 200 D. 1000
Mathematics
1 answer:
boyakko [2]3 years ago
8 0

Answer:

There are 600 students in this school.

Step-by-step explanation:

Let p represent the total population of the school.

Then (1/3)p represents the number of students who like math.  Subtracting this (1/3)p from p gives an expression representing those who do not like math:  

p - (1/3)p = (2/3)p

400 students do not like math, so (2/3)p = 400.

Solve this for p by multiplying both sides by (3/2):

(3/2)(2/3)p = (3/2)(400), which simplifies to p = 600.

There are 600 students in this school.

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Evaluate the expression -8x + 5 - 2x - 4 + 5x when x = 2 before and after simplifying.
Alex777 [14]

Answer:

Step-by-step explanation:

all we have to do is plug in 2 for x into the equation:

-8(2) + 5 -2(2) -4 + 5(2)

-16 + 5 -4 -4 + 10

-11 -8 + 10

-19 + 10

the answer is

-9

to simplify the equation we’ll combine like terms

-8x + 5 -2x -4 + 5x

-10x + 1 + 5x

-5x + 1

now we’ll plug in 2 for x

-5(2) + 1

-10 + 1

the answer is still

-9

5 0
3 years ago
Read 2 more answers
If you invest $823 at an interest rate of 3 percent,how much money will you have in total afer nine years?​
valentinak56 [21]

Answer:

$1,045.21

Step-by-step explanation:

7 0
3 years ago
Points E, F, and D are on circle C, and angle G measures 60°. The measure of arc EF equals the measure of arc FD.
galben [10]

Answer:

∠EFD ≅ ∠EGD ⇒ A

Arc ED ≅ arc FD ⇒ C

m arc FD = 120° ⇒ E

Step-by-step explanation:

Let us revise some facts

  1. Equal chords subtended equal arcs
  2. The measure of an inscribed angle is one-half the measure of the central angle which subtended by the same arc
  3. The measure of a central angle is equal to the measure of its subtended arc
  4. If one angle of an isosceles triangle measure 60° then the triangle is equilateral
  5. The sum of the measures of the interior angles of any quadrilateral is 360°

In the quadrilateral  CDGE

∵ m∠G = 60°

∵ m∠GDC = m∠GEC = 90°

- By using the 5th rule above

∴ m∠G + m∠GDC + m∠DCE + m∠GEC = 360°

∴ 60 + 90 + m∠DCE + 90 = 360

∴ 240 + m∠DCE = 360

- Subtract 240 from both sides

∵ m∠DCE = 120°

In circle C

∵ ∠DCE is a central angle subtended by arc DE

∵ ∠DFE is an inscribed angle subtended by arc DE

- By using the 2nd rule above

∴ m∠DFE = \frac{1}{2} m∠∠DCE

∵ m∠DCE = 120°

∴ m∠DFE = \frac{1}{2} (120)

∴ m∠DFE = 60°

- That means ∠EFD ≅ ∠EGD because their measure is 60°

∴ ∠EFD ≅ ∠EGD

In Δ EFD

∵ EF = FD

∵ m∠DFE = 60°

- By using the 4th rule above

∴ Δ EFD is an equilateral triangle

∴ ED = FD = FE

In circle C

∵ Side ED subtended by arc ED

∵ Side FD subtended by FD

∵ Side ED ≅ side FD ⇒ proved

- By using the 1st rule above

∴ Arc ED ≅ arc FD

∵ m∠ECD = 120°

∵ ∠ECD is a central angle subtended by arc ED

- By using the 3rd rule above

∴ m∠ECD = m arc ED

∴ m of arc ED = 120°

∵ Arc ED ≅ arc FD

∴ m arc ED = m arc FD

∴ m arc FD = 120°

5 0
3 years ago
Read 2 more answers
A toy rocket is launched straight up from the top of a building. The function that models the height as a function of time is h(
kicyunya [14]

Answer: 50 ft

Step-by-step explanation:

The correct function is h(t)=-16t^2+200t+50.

Hi, to answer this question we simply have to replace t =0 in the function given:

h(t)=-16t^2+200t+50.

h (0) = -16t^2+200t+50.

h(0) = 50

When the time is 0, the rocket is at the top of the building.

The rocket was launched from a 50 ft height.

Feel free to ask for more if needed or if you did not understand something.  

4 0
3 years ago
For the equation below, x is the input and y is the output. y = -4x + 3 If the input is -8, then the output is
KonstantinChe [14]

Answer:

35

Step-by-step explanation:

If is given the value -8 as it is the input then -->

y = -4(-8) + 3

Negative four times negative 8 is positive 32 so

y= 32 + 3

And 32 plus 3 is 35


7 0
3 years ago
Read 2 more answers
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