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IgorC [24]
4 years ago
12

At the Mobil Station on Long Beach Road, it costs $65 for 18 gallons of unleaded gasoline. If you only have $50. how many gallon

s could you purchase (to the nearest tenth of a gallon)?
Mathematics
2 answers:
Helga [31]4 years ago
6 0
13.8 gallons

Rounded from 13.8462

The equation you would use is (65/18)=(50/x) solve for x
Liula [17]4 years ago
4 0
You could purchase 13.8 gallons.
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V= <em>lwh</em><em> </em>or <em>l</em><em> </em><em>*</em><em>w</em><em>*</em><em>h</em>

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2 years ago
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Step-by-step explanation:

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A right triangle has base x meters and height h meters, where h is constant and x changes with respect to time t, measured in se
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The relationship between dθ/dt, the rate of change of θ with respect to time, and dx/dt, the rate of change of x with respect to time is \frac{d\theta}{dt}  = \frac{h}{x\sqrt{x^2+y^2} }\frac{dx}{dt}

Given the following parameters:

  • Adjacent side = x
  • Opposite side = h
  • The angle of elevation = θ

According to SOH CAH TOA identity;

tan \theta =\frac{Opposite}{Adjacent}

Substitute the given values into the formula

tan \theta =\frac{h}{x}

\theta= tan^{-1}\frac{h}{x}

Differentiate with respect to x

\frac{d \theta}{dx} = \frac{h}{x\sqrt{x^2+y^2} }

According to the chain rule,

\frac{d\theta}{dt} =\frac{d\theta}{dx} \times \frac{dx}{dt}\\\frac{d\theta}{dt}  = \frac{h}{x\sqrt{x^2+y^2} }\frac{dx}{dt}

Hence the relationship between dθ/dt, the rate of change of θ with respect to time, and dx/dt, the rate of change of x with respect to time is \frac{d\theta}{dt}  = \frac{h}{x\sqrt{x^2+y^2} }\frac{dx}{dt}

Learn more on the rate of change here: brainly.com/question/11883878

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