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3 years ago

Write an equivalent expression: 5.2x+8+2.1x-3 if you get it wrong its ok :)

Mathematics

2 answers:

Zinaida [17]3 years ago

6 0

This should be your answer

vodka [1.7K]3 years ago

4 0

7.3x+5 because I had that question in my old school and I got it right so hop this help you

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I need answer ASAP If f(x) = 2x+1 and g(x) = 3x-2 Find f[g(1)] =

Nadya [2.5K]

Answer:

f[g(1)] = 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = 2x + 1

g(x) = 3x - 2

Step 2: Find g(1)

Substitute in x: g(1) = 3(1) - 2
Multiply: g(1) = 3 - 2
Subtract: g(1) = 1

Step 3: Find f[g(1)]

Substitute in g(1): f[g(1)] = 2(1) + 1
Multiply: f[g(1)] = 2 + 1
Add: f[g(1)] = 3

7 0

3 years ago

f(x) = 3 cos(x) 0 ≤ x ≤ 3π/4 evaluate the Riemann sum with n = 6, taking the sample points to be left endpoints. (Round your ans

Kruka [31]

Answer:

$\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558$

Step-by-step explanation:

We want to find the Riemann sum for $\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx$ with n = 6, using left endpoints.

The Left Riemann Sum uses the left endpoints of a sub-interval:

$\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)$

where $\Delta{x}=\frac{b-a}{n}$ .

Step 1: Find $\Delta{x}$

We have that $a=0, b=\frac{3\pi }{4}, n=6$

Therefore, $\Delta{x}=\frac{\frac{3 \pi}{4}-0}{6}=\frac{\pi}{8}$

Step 2: Divide the interval $\left[0,\frac{3 \pi}{4}\right]$ into n = 6 sub-intervals of length $\Delta{x}=\frac{\pi}{8}$

$a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b$

Step 3: Evaluate the function at the left endpoints

$f\left(x_{0}\right)=f(a)=f\left(0\right)=3=3$

$f\left(x_{1}\right)=f\left(\frac{\pi}{8}\right)=3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}=2.77163859753386$

$f\left(x_{2}\right)=f\left(\frac{\pi}{4}\right)=\frac{3 \sqrt{2}}{2}=2.12132034355964$

$f\left(x_{3}\right)=f\left(\frac{3 \pi}{8}\right)=3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=1.14805029709527$

$f\left(x_{4}\right)=f\left(\frac{\pi}{2}\right)=0=0$

$f\left(x_{5}\right)=f\left(\frac{5 \pi}{8}\right)=- 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=-1.14805029709527$

Step 4: Apply the Left Riemann Sum formula

$\frac{\pi}{8}(3+2.77163859753386+2.12132034355964+1.14805029709527+0-1.14805029709527)=3.09955772805315$

$\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558$

5 0

3 years ago

One fourth the sum of x and ten is identical to x minus 4."

Lynna [10]

Answer and Step-by-step explanation:

We are given the word format of an equation.

Let's right it out in numerical form.

$\frac{1}{4} (x + 10) = x - 4$

The first part says One fourth the sum of x and 10

The sum of x and 10 would be shown as x + 10, and one fourth of that means that $\frac{1}{4}$ is multiplying (x + 10).

In this case, identical would mean equal to.

So, $\frac{1}{4}$ (x + 10) would be = to something.

It says that it is identical to x minus 4 (x - 4).

$\frac{1}{4} (x + 10) = x - 4$ is the equation.

#teamtrees #PAW (Plant And Water)

5 0

3 years ago

There are two balance beams at the gym.one is 15 feet long ,theother is 162 inches long.which beam is longer?

Oduvanchick [21]

12 inches = 1 foot

Let x=length of 2nd balance beam in feet

by ratio and proportion

1/12 = x/162

multiply noth sides by 162 to isolate x

(1/12)(162) = (x/162)(162)

162/12 = x

13.5 = x

Source -->https://socratic.org/questions/at-the-gym-one-balance-beam-is-15-feet-long-while-the-other-is-162-in...<--

can you help me? brainly.com/question/3131429

7 0

3 years ago

Read 2 more answers

Answer answer it it it

lakkis [162]

Answer:

May-June

Step-by-step explanation:

Notice that:

● during April-May period the Badminton memberships rate of increase is greather then Swimming's since the graph of Badminton is showing a faster increase.

● During June-July period, both functions are decreasing so this period does not satisfy our condition.

● During May-June The Swimming memberships growed faster than Badminton's so its rate of increase is greather than Badminton's.

● during August-September period, The swimming memeberships are increasing slower than Badminton's

So the answer is May-June

8 0

3 years ago