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melisa1 [442]
3 years ago
13

1/2y^2(6x+2y+12x-2y) is equivalent

Mathematics
1 answer:
vazorg [7]3 years ago
3 0
The answer is 9y^2x(the 2 goes on top were the arrow is ) Hope this was helpful!
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a traffic survey showed that 1,048 cars passed through an intersection in one hour. which is the best estimate of how many cars
Nikitich [7]
8,384 cars will pass

8 0
3 years ago
a pyramid has a regular hexagonal base with side length of 4 and a slant height of 6. what is the total area of the pyramid
Stels [109]
So hmm notice the picture below

the pyramid itself, is really, just one regular hexagon, at the bottom
and 6 triangles, stacked up at each other at the edges

now, if you just get the area of the regular hexagon, and the 6 triangles, add them up, that'd be the total surface area of the pyramid then
\bf \textit{area of a regular polygon}\\\\
A=\cfrac{1}{4}\cdot  n\cdot  s^2\cdot  cot\left( \frac{180}{n} \right)\qquad 
\begin{cases}
n=\textit{number of sides}\\
s=\textit{length of a side}\\
\frac{180}{n}=\textit{angle in degrees}\\
----------\\
n=6\\
s=4
\end{cases}\\\\\\ A=\cfrac{1}{4}\cdot  6\cdot  4^2\cdot  cot\left( \frac{180}{6} \right)

now, for the triangles, well, area of a triangle is 1/2 bh, as you'd know, and you have both

8 0
3 years ago
Which describes the relationship between the number of tickets sold and the profit?
bulgar [2K]
Each ticket sold yields 9$ of profit
7 0
2 years ago
What is the value of the correlation coefficient r of the data set?
enyata [817]

The correct option will be:  C) 0.84

<u><em>Explanation</em></u>

Formula for Correlation coefficient :

r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}

First, for each point(x, y), we need to calculate x², y² and xy .

Then, we will find sum all x, y, x², y² and xy, which gives us Σx, Σy, Σx², ∑y² and Σxy

<em>(Please refer to the attached image for the table )</em>

Here we got, ∑x = 44 , ∑y = 183 , ∑x² = 362 , ∑y² = 6575 and ∑xy = 1480

'n' is the total number of data set, which is 7 here.

So, plugging those values into the above formula..........

r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}\\ \\ r=\frac{7(1480)-(44)(183)}{\sqrt{[7(362)-(44)^2][7(6575)-(183)^2]}}\\ \\ r=\frac{10360-8052}{\sqrt{(598)(12536)}}\\ \\ r=\frac{2308}{\sqrt{7496528}}\\ \\ r=0.84

So, the value of the correlation coefficient is 0.84

4 0
3 years ago
Read 2 more answers
Help plz:)))I’ll mark u Brainliest
shepuryov [24]

Answer:

Yes they are congruent by SAS (wrong answer)

Edit: the correct answer is by HL

5 0
3 years ago
Read 2 more answers
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