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DedPeter [7]
2 years ago
7

Find the absolute maximum and minimum of the function on the given domain. f (x comma y )equals 2 x squared plus 5 y squared on

the closed triangular plate bounded by the lines x equals 0 comma y equals 0 comma y plus 2 x equals 2 in the first quadrant

Mathematics
1 answer:
prisoha [69]2 years ago
5 0

Answer:

The absolute maximum of f(x,y) in the triangle plate is 20, and the absolute minimum is 0.

Step-by-step explanation:

We have the function f(x,y)=2x^2+5y^2 and we want to the the absolute maximum and minimum in the bounded region determined by the lines y=0, x=0 and y+2x=2, and we will call it A.

Usually, in this kind of problem, the first step is to assure the existence of the absolute maximum and minimum. The general procedure is to show that the function is continuous and the region is closed and bounded.

It is no difficult to see that the function f(x,y) is continuous in the whole plane, so it is in the given region. Moreover, the region is closed and bounded. So, we can assure the existence of the absolute minimum and maximum of f(x,y) in the triangle plate.

The second step is to find the critical point(s) of the function in the interior of A. In order to do that we must calculate the partial derivatives:

\frac{\partial f}{\partial x}(x,y) = 4x

\frac{\partial f}{\partial y}(x,y) = 10y

Recall that the critical points are those that makes zero both partial derivatives. So, we need to solve the system of equations

4x=0

10y=0

that has as only solution the point (x,y)=(0,0). Now, the point (0,0) is not in the interior of A but in the boundary.

As the function has no critical points <em>inside</em> the region A, we must look for the extremal values of f(x,y) in the boundary of A.

In order to make the following explanation simpler there is a figure attached, where the triangle plate A has been drawn.

Now, we need to give ‘‘parametric’’ expressions for the boundary of the set A. Notice that:

  • The segment AC has the form (x,y) = (x,0) with x\in[0,1].
  • The segment AB has the form (x,y) = (0,y) with y\in[0,2].
  • The segment BC has the form (x,y) = (x,2-2x) with x\in[0,1]

The last representation was deduced from the equation of the line, because  y+2x=2 is equivalent to y=2-2x.

Now, let us analyze the behavior of f(x,y) in each of the sides of the triangle. The procedure will be to find the maximal and minimum of f(x,y) in each side of the triangle, and finally we will compare them and take the minimal value as the absolute minimum and the maximal as the absolute maximum.

<em>The segment </em>AC. In this case we have f(x,0) =2x^2 with x\in[0,1]. So, we have reduced our two variable function to one variable function, which has a simpler behavior. Here, we can affirm that the maximal value of f(x,y) in AC is obtained when x=1 and is f(1,0)=2, and the minimal is obtained when x=0 and is f(0,0)=0.

<em>The segment </em>AB. In this case we have f(0,y) =5y^2 with y\in[0,2]. So, again, we have reduced our two variable function to one variable function, which has a simpler behavior. Here, we can affirm that the maximal value of f(x,y) in AB is obtained when y=2 and is f(0,2)=20, and the minimal is obtained when y=0 and is f(0,0)=0.

<em>The segment </em>BC. In this case we have

f(x,2-2x) =2x^2 + 5(2-2x)^2=22x^2-40x+20 with x\in[0,1].

So, we have reduced our two variable function to one variable function. In order to obtain the extremal values of f(x,y) in BC, we must find the extremal values of 22x^2-40x+20=g(x) in the interval [0,1]. Though not so easy as the previous two, this problem is easier that the original.

So, we calculate the derivative of the function g(x):

g'(x) = 44x-40, which has only one zero in the interval [0,1] and it is 40/44. To obtain the minimum and maximum of g(x) in [0,1] we only need to evaluate g(0), g(40/44) and g(1). Then,

  • g(0) = 20
  • g(40/44) \approx 1.818
  • g(1) = 2

So, we can affirm that the maximal value of f(x,y) in BC is obtained when x=0 and is f(0,2)=20, and the minimal is obtained when x=40/44 and is f(40/44,0.181)=1.181.

<em>Conclusion</em>: The extremal values of f(x,y) obtained in the boundary of the triangle are:

  • f(1,0)=2 and f(0,0)=0.
  • f(0,2)=20 and f(0,0)=0.
  • f(0,2)=20 and f(40/44,0.181)=1.181.

So, of all those values the minimum is f(0,0)=0 and the maximum is f(0,2)=20. This means that

\max_{(x,y)\in A}\{f(x,y)\} = 20

\min_{(x,y)\in A}\{f(x,y)\} = 0.

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Answer:

G.  ABD = 74

H.  DBC = 206

I.  XYW = 33.75

J.  WYZ = 46.25

Step-by-step explanation:

For G and H: You have a straight line (ABC) with another line coming off of it, creating two angles (ABD and DBC).  A straight line has an angle of 180 degrees.  This means that the two angles from the straight line when combined will give you 180 degrees.  Solve for x.

ABD + DBC = ABC

(1/2x + 20) + (2x - 10) = 180

1/2x + 20 + 2x - 10 = 180

5/2x + 10 = 180

5/2x = 170

x = 108

Now that you have x, you can solve for each angle.

ABD = 1/2x + 20

ABD = 1/2(108) + 20

ABD = 54 + 20

ABD = 74

DBC = 2x - 10

DBC = 2(108) - 10

DBC = 216 - 10

DBC = 206

For I and J:  For these problems, you use the same concept as before.  You have a right angle (XYZ) that has within it two other angles (XYW and WYZ).  A right angle has 90 degrees. Combine the two unknown angles and set it equal to the right angle.  Solve for x.

XYW + WYZ = XYZ

(1 1/4x - 10) + (3/4x + 20) = 90

1 1/4x - 10 + 3/4x + 20 = 90

2x + 20 = 90

2x = 70

x = 35

Plug x into the angle values and solve.

XYW = 1 1/4x - 10

XYW = 1 1/4(35) - 10

XYW = 43.75 - 10

XYW = 33.75

WYZ = 3/4x + 20

WYZ = 3/4(35) + 20

WYZ = 26.25 + 20

WYZ = 46.25

3 0
3 years ago
The equation (2x^2 - 1)(3x+2) = (2x²)(3x) + (2x²)(2) + (-1)(3x)+(-1)(2) is an example
Nookie1986 [14]

The method used is Distributive Property.

<h3>What is Distributive property?</h3>

The Distributive Property is an algebraic property that is used to multiply a single value and two or more values within a set of parenthesis.

Given:

(2x² - 1)(3x+2) = (2x²)(3x) + (2x²)(2) + (-1)(3x)+(-1)(2)

Here the property used is Distributive property.

Because distributive property in this way

a*(b+c)= a*b+ a*c

This is how a is being multiplied by with b and c.

Learn more about this Distributive property here:

brainly.com/question/4136433

#SPJ1

8 0
1 year ago
How many solutions does this have ?
Gemiola [76]
It has one solution that I know of
8 0
3 years ago
Read 2 more answers
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