Select the correct answer. Given: ∆ABC Prove: A midsegment of ∆ABC is parallel to a side of ∆ABC. Statement Reason 1. Define the
2 answers:
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Given that,
In <u>triangle TPQ, </u>
- RS || PQ,
- RS = 3 cm,
- PQ = 6 cm,
- ar(∆ TRS) = 15 sq. cm
As it is given that, <u>RS || PQ</u>
So, it means
⇛∠TRS = ∠TPQ [ Corresponding angles ]
⇛ ∠TSR = ∠TPQ [ Corresponding angles ]
<u>Now, We know </u>
Area Ratio Theorem,
This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.
