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3 years ago

12

Need help.please on number one

2 answers:

Nezavi [6.7K]3 years ago

6 0

6 sides because it's a triangle and 2 angles

professor190 [17]3 years ago

3 0

The answer is 12 including both sides and angles.

When you cut a square piece of paper from one point to the opposite point it should make two triangles.

Thus each triangle has 3 sides and 3 angles so two triangles has 6 angles and 6 sides

So 12, sides and angles added together.

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An office supply store sells 8 pens for $4.00. If this relationship is graphed with the number of pens on the x-axis and the cos

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Answer:

Step-by-step explanation:

B

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3 years ago

Just need the equation

Anna007 [38]

$a. $ x = -2\\b. $ x = \frac{3}{2} \\c. $ x = 0\\d. $ x = -\frac{1}{5}$

Each of the equations can be solved as shown below:

a. $3x + 7 = - x - 1$

$3x + 7 + x = - x - 1 + x$ (<em>addition property of equality</em>)

$4x + 7 = - 1\\4x + 7 - 7 = -1-7$ (<em>Subtraction property of equality</em>)

$4x = -8\\\frac{4x}{4} = \frac{-8}{4}$ <em> (Division property of equality)</em>

<em /> $x = -2$

b. $1 - 2x + 5 = 4x - 3\\$

<em>Add like terms </em>

<em /> $6 - 2x = 4x - 3\\\\6 - 2x - 6 = 4x - 3 - 6$ (<em>Subtraction property of equality</em>)

$- 2x = 4x - 9\\-2x - 4x = 4x -9 - 4x$ <em> (Subtraction property of equality)</em>

<em /> $-6x = -9 \\\frac{-6x}{-6} = \frac{-9}{-6}$ <em> (Division property of equality)</em>

<em /> $x = \frac{3}{2}$

c. $4x - 2 + x =-2 + 2x\\$

$5x - 2 = -2 + 2x\\5x - 2x = -2 + 2\\3x = 0\\ x = \frac{0}{3} \\x = 0$

d. $3x - 4 + 1 = - 2x -5 + 5x\\$

$3x - 3 = - 7x -5\\3x + 7x = 3 - 5\\10x = -2\\x = \frac{-2}{10} \\x = -\frac{1}{5}$

<em>The value of x in each </em><em>equation</em><em> are:</em>

<em /> $a. $ x = -2\\b. $ x = \frac{3}{2} \\c. $ x = 0\\d. $ x = -\frac{1}{5}$

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brainly.com/question/1527981

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3 years ago

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Anestetic [448]

Answer:

Answer: 9

Step-by-step explanation:

${ \tt{f(x) = 3( {8)}^{x} + 6 }}$

• For f(0), substitute x with zero:

${ \tt{f(0) = 3( {8)}^{0} + 6}} \\ \\ { \tt{f(0) = (3 \times 1) + 6}} \\ \\ { \tt{f(0) = 3 + 6}} \\ \\ { \boxed{ \tt{ \: f(0) = 9 \: }}}$

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2 years ago

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Well,

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