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Gennadij [26K]
3 years ago
6

A scientist investigates a new substance and finds that at 35° C, 146.2 grams will dissolve in 200.0 grams of water. Which simil

ar experiment could be used to support the scientist’s results?
One performed at a higher temperature
One performed in a different part of the world
One performed using a solvent other than water
One performed with an alternate substance
Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0
I would say choice A
but im not absolutely sure
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A teacher passes cards out to students. She has 52 cards. She gives one card to each student at a time to each student until all
Zarrin [17]
The problem presents 2 variables and 2 conditions to follow to determine the approach in solving the problem. The variables are 52 cards, and 9 cards. The 2 conditions presented would be the teacher giving out one card to each student at a time to each student until all of them are gone. The second variable is more likely made as a clue and the important variable that gives away the approach to be used. The approach to be used is division. This is to ensure that there will be students receiving the 9 cards. Thus, we do it as this: 52 / 9 = ?

The answer would be 5.77778 (wherein 7 after the decimal point is infinite and 8 would just be the rounded of number). This would ensure us that there will be 5 students that can receive 9 cards but there will be 7 cards remaining which goes to the last student, which is supposed to be 8 since she gives one card to each student at a time to each student. So the correct answer would be just 4 students. The fifth student will only receive 8 cards and the last student would have 8, too.
6 0
3 years ago
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A 1.50 liter sample of dry air in a cylinder exerts a pressure of 3.00 atmospheres at a temperature of 25oC. Without change in t
cricket20 [7]
The answer is 4.5 l

To calculate this, we will use the Boyle's law using constant k, pressure P, and volume V:

 PV = k

We can forget temperature since it is constant.

We have:

P1V1 = k

P2V2 = k

So, P1V1 = P2V2

P1 = 3 atm

V1 = 1.5 l

P2 = 1 atm

V2 = ?

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P1V1 = P2V2

3 atm * 1.5 l = 1 atm * V2

4.5 atm/l = 1 atm * V2

V2 = 4.5 atm l / 1 atm

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5 0
3 years ago
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Y = x +4<br> 3x + y = 16
Vesna [10]

Answer:

x= 3 while fo y = 7 that's the answer

5 0
3 years ago
Find the area of the shape shown below. I reallly need help and do not put a unbelieable answer.
larisa [96]

Answer:

63/2 or 31.5

Step-by-step explanation:

we can split this shape into 2, a triangle and a rectangle

A triangle = bh/2 = 7*3*1/2 = 21/2

A rectangle = b*h = 3*7 = 21

21/2 + 21 = 63/2

3 0
3 years ago
(b) The perimeter of a rectangular painting is 250 cm.
hodyreva [135]
53x2=106
250-106= 144
144/2=72
The length is 72cm
4 0
3 years ago
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