PLEASE HELP WILL GIVE 10 POINTS! Subtract. −3 2/7−(−5/7)

Mathematics

1 answer:

SashulF [63]3 years ago

6 0

your answer would be -2.57142857143

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Mafalda has a save percentage of 0.7380.7380, point, 738 so far this hockey season. Last season, her save percentage was 0.5850.

Snowcat [4.5K]

Answer:

0.153

Step-by-step explanation:

We have been given that Mafalda has a save percentage of 0.738 so far this hockey season. Last season, her save percentage was 0.585.

To find improvement in Mafalda's save percentage we will subtract last season's save percentage from this season's save percentage.

$0.738-0.585=0.153$

Therefore, Mafalda's save percentage improved by 0.153.

6 0

3 years ago

Read 2 more answers

Can somebody please help me with work answer Pleaseee

liberstina [14]

Answer:

yes

Step-by-step explanation:

7 0

3 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$