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3 years ago

Which statement correctly compares the value of the 7 before the decimal in the number 257.76 to the 7 after the decimal?

Mathematics

2 answers:

drek231 [11]3 years ago

4 0

Easy
the value of the 7's in the decimal number, 257.76 is 0nes and tenths

Maurinko [17]3 years ago

3 0

Answer:

The 7 before the decimal in the number 257.76 is ten times greater than the 7 after the decimal

Step-by-step explanation:

The number located one place to the left of the decimal point is called ones.

The number located one place to the right of the decimal point is called tenth.

In this case, the ones is 10 times greater than the tenth because they are numerically equal.

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Use the distributive property to expand Negative 4 (Negative two-fifths + 3 x). Which is an equivalent expression?

Natalija [7]

Answer:

the answer is the last one

Step-by-step explanation:

so the answer is d

5 0

3 years ago

Read 2 more answers

13 = m/4 + 7 can you show work too

lukranit [14]

The correct value of this equation is m = 24

<h3>Resolution method</h3>

This equation contains a fractional term. We note that the denominator of this equation is the term 4. Therefore, we will multiply the sides by 4:

13 = m/4 + 7

13 . 4 = 4(m/4) + 7 . 4

52 = m + 28

Now, let's isolate the variable "as negative" and after the equality - we'll be subtracting the terms:

52 = m + 28

-m = 28 - 58

-m = -24

m = 24

Therefore, the correct value of this equation will be m = 24

7 0

2 years ago

In a large population of college-educated adults, the mean IQ is 118 with a standard deviation of 20. Suppose 200 adults from th

cricket20 [7]

Answer: 0.0793

Step-by-step explanation:

Let the IQ of the educated adults be X then;

Assume X follows a normal distribution with mean 118 and standard deviation of 20.

This is a sampling question with sample size, n =200

To find the probability that the sample mean IQ is greater than 120:

P(X > 120) = 1 - P(X < 120)

Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n

Where; X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size

Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)

= 1 - P(Z< 1.41)

The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207

Thus; P(X< 120) = 1 - 0.9207

= 0.0793

3 0

3 years ago

Write a proportion for 56% of a number is 244

Misha Larkins [42]

$\frac{56}{100} = \frac{244}{x}$ So, You cross multiply and get 56x=244(100). Simplify and you get 56x=24400. Divide each side by 56 and you get 435.71. 56% of about 435.71 is 244.

6 0

3 years ago

How do i calculate the first quartile and the third quartile??? !!!please help!!!

diamong [38]

Answer: The Median: 78, The First Quartile: 63, and The Third Quartile: 99

Step-by-step explanation: Ok, so let's put the data set from least to greatest....

(63, 63, 76,) (77, 79,) (84, 99, 99)

First Quartile Third Quartile

First, let's find the median, since you made a little mistake...

77 + 79 = 156

156 ÷ 2 = 78

The median is 78!

Now, let's determine the first quartile and the third quartile.

For the the first quartile/third quartile it'll be the middle number, if it's even we'll do the same extra step just like we'll do for the median. In this case it's not even therefore...

First Quartile: 63

Third Quartile: 99

I hope this helps!

5 0

3 years ago