Answer:
1
Step-by-step explanation:
The first step is to understand what the integrand looks like. (See the graph below.)
It is -1 for x < 0 and +1 for x > 0. Thus, the value of this integral is ...
![\int\limits^0_{-1} {-1} \, dx + \int\limits^2_0 {1} \, dx=-1+2=1](https://tex.z-dn.net/?f=%5Cint%5Climits%5E0_%7B-1%7D%20%7B-1%7D%20%5C%2C%20dx%20%2B%20%5Cint%5Climits%5E2_0%20%7B1%7D%20%5C%2C%20dx%3D-1%2B2%3D1)
_____
Essentially, you treat the absolute value as a piecewise linear function. This is the same way you treat an absolute value in any equation or inequality.
Here, this means you divide the integral into two parts: one where the integrand is -x/x, and one where it is +x/x.
The answer is B. because (4-10) equals -6 and (4-4) equals 0. -6 times 0 is 0.
Answer:
Probability can not exceed 1. If an event has a probability of 1, then the event is certain to happen. Example: if you have a bag of 5 blue marbles the probability that you will pull out a blue is 5/5 which simplifies to 1.
Step-by-step explanation:
#1)
A) b = 10.57
B) a = 22.66; the different methods are shown below.
#2)
A) Let a = the side opposite the 15° angle; a = 1.35.
Let B = the angle opposite the side marked 4; m∠B = 50.07°.
Let C = the angle opposite the side marked 3; m∠C = 114.93°.
B) b = 10.77
m∠A = 83°
a = 15.11
Explanation
#1)
A) We know that the sine ratio is opposite/hypotenuse. The side opposite the 25° angle is b, and the hypotenuse is 25:
sin 25 = b/25
Multiply both sides by 25:
25*sin 25 = (b/25)*25
25*sin 25 = b
10.57 = b
B) The first way we can find a is using the Pythagorean theorem. In Part A above, we found the length of b, the other leg of the triangle, and we know the measure of the hypotenuse:
a²+(10.57)² = 25²
a²+111.7249 = 625
Subtract 111.7249 from both sides:
a²+111.7249 - 111.7249 = 625 - 111.7249
a² = 513.2751
Take the square root of both sides:
√a² = √513.2751
a = 22.66
The second way is using the cosine ratio, adjacent/hypotenuse. Side a is adjacent to the 25° angle, and the hypotenuse is 25:
cos 25 = a/25
Multiply both sides by 25:
25*cos 25 = (a/25)*25
25*cos 25 = a
22.66 = a
The third way is using the other angle. First, find the measure of angle A by subtracting the other two angles from 180:
m∠A = 180-(90+25) = 180-115 = 65°
Side a is opposite ∠A; opposite/hypotenuse is the sine ratio:
a/25 = sin 65
Multiply both sides by 25:
(a/25)*25 = 25*sin 65
a = 25*sin 65
a = 22.66
#2)
A) Let side a be the one across from the 15° angle. This would make the 15° angle ∠A. We will define b as the side marked 4 and c as the side marked 3. We will use the law of cosines:
a² = b²+c²-2bc cos A
a² = 4²+3²-2(4)(3)cos 15
a² = 16+9-24cos 15
a² = 25-24cos 15
a² = 1.82
Take the square root of both sides:
√a² = √1.82
a = 1.35
Use the law of sines to find m∠B:
sin A/a = sin B/b
sin 15/1.35 = sin B/4
Cross multiply:
4*sin 15 = 1.35*sin B
Divide both sides by 1.35:
(4*sin 15)/1.35 = (1.35*sin B)/1.35
(4*sin 15)/1.35 = sin B
Take the inverse sine of both sides:
sin⁻¹((4*sin 15)/1.35) = sin⁻¹(sin B)
50.07 = B
Subtract both known angles from 180 to find m∠C:
180-(15+50.07) = 180-65.07 = 114.93°
B) Use the law of sines to find side b:
sin C/c = sin B/b
sin 52/12 = sin 45/b
Cross multiply:
b*sin 52 = 12*sin 45
Divide both sides by sin 52:
(b*sin 52)/(sin 52) = (12*sin 45)/(sin 52)
b = 10.77
Find m∠A by subtracting both known angles from 180:
180-(52+45) = 180-97 = 83°
Use the law of sines to find side a:
sin C/c = sin A/a
sin 52/12 = sin 83/a
Cross multiply:
a*sin 52 = 12*sin 83
Divide both sides by sin 52:
(a*sin 52)/(sin 52) = (12*sin 83)/(sin 52)
a = 15.11
Answer:
cups plaster of paris.
Step-by-step explanation:
Given:
for one batch of sidewalk chalk =
cup plaster of paris.
Number of bathes = 3
We need to find quantity of plaster of paris.
Solution:
For making 1 batch of sidewalk chalk =
cup plaster of paris.
For making 3 batches of sidewalk chalk =
cup plaster of paris.
![= 3\times \frac{2\times 1+1}{2}](https://tex.z-dn.net/?f=%3D%203%5Ctimes%20%5Cfrac%7B2%5Ctimes%201%2B1%7D%7B2%7D)
![= 3\times \frac{2+1}{2}](https://tex.z-dn.net/?f=%3D%203%5Ctimes%20%5Cfrac%7B2%2B1%7D%7B2%7D)
![= 3\times \frac{3}{2}](https://tex.z-dn.net/?f=%3D%203%5Ctimes%20%5Cfrac%7B3%7D%7B2%7D)
![= \frac{3\times 3}{2}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B3%5Ctimes%203%7D%7B2%7D)
![= \frac{9}{2}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B9%7D%7B2%7D)
![=4\frac{1}{2}](https://tex.z-dn.net/?f=%3D4%5Cfrac%7B1%7D%7B2%7D)
Therefore, he needed
cups plaster of paris.