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dedylja [7]
3 years ago
11

Write a program whose input is two integers and whose output is the two integers swapped. Ex: If the input is: 38 then the outpu

t is: 83 Your program must define and call a function. SwapValues returns the two values in swapped order. void SwapValues (int* userVali, int* userVal2) LAB ACTIVITY 6.22.1: LAB: Swapping variables 22.1. LAB 0/10 ] main.c Load default template... #include /* Define your function here */ int main(void) { Ovo AWN /* Type your code here. Your code must call the function. */ return 0; 10 }
Computers and Technology
1 answer:
Likurg_2 [28]3 years ago
6 0

Answer:

Following are the program in the C++ Programming Language.

#include <iostream>

using namespace std;

//define function for swapping

void SwapValues(int* userVal1,int* userVal2){  

//set integer variable to store the value

int z = *userVal1;

//interchange their value

*userVal1 = *userVal2;  

//interchange their value

*userVal2 = z;

}

//define main method

int main()

{    

//declare variables

int x,y;

//get input from the user

cin>>x>>y;

//Call the method to swap the values

SwapValues(&x,&y);

//print their values

cout<<x<<" "<<y;

return 0;

}

<u>Output</u>:

3 8

8 3

Explanation:

<u>Following are the description of the program</u>.

  • Firstly, we define required header file and function 'SwapValues()', pass two pointer type integer variables in argument that is 'userVal1' and 'userVal2'.
  • Set integer data type variable 'z' and initialize the value of 'userVal1' in it, then initialize the value of 'userVal2' in 'userVal1' and then initialize the value of 'z' in 'userVal2'.
  • Finally, define the main method in which we set two integer type variables and get input from the user in it then, call and pass those variables and print it.
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Answer: True

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A digital computer has a memory unit with 16 bits per word. The instruction set consists of 72 different operations. All instruc
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Answer:

a. 7 bits b. 9 bits c. 1 kB d. 2¹⁶ - 1

Explanation:

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72 = 64 + 8 = 2⁶ + 8

Since n must be an integer value, the closest value of n that would contain 72 different operations is n = 7. So, 2⁷ = 128

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bits left = bits per word - opcode bit = 16 - 7 = 9 bits

c. What is the maximum allowable size for memory?

Since there are going to be 2⁹ bits to addresses each word and 16 bits  for each word, the maximum allowable size for memory is thus 2⁹ × 16 = 512 × 16 = 8192 bits.

We convert this to bytes

8192 bits × 1 byte/8 bits = 1024 bytes = 1 kB

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Explanation:

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Answer:

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