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Monica [59]
3 years ago
14

An incurred cost that cannot be recovered, which is irrelevant for all decisions about the future, is included in the projected

cost of a project. According to "Thinking Like an Economist," this an example of:_____________.
Computers and Technology
1 answer:
iragen [17]3 years ago
3 0

Answer:

An incurred cost that cannot be recovered, which is irrelevant for all decisions about the future, is included in the projected cost of a project. According to "Thinking Like an Economist," this an example of:<u> Failing to ignore sunk costs</u>

Explanation:

A sunk cost is a cost that cannot be recovered or changed and is independent of any future costs a business may incur. Since decision-making only affects the future course of business, sunk costs should be irrelevant in the decision-making process

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Search Engine

Explanation:

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Answer:

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GenXTech is a growing company that develops gaming applications for military simulations and commercial clients. As part of its
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Answer:

an enterprise architecture

Explanation:

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12.2 Sort an array in ascending order Write a program that gets a list of integers from input, and outputs the integers in ascen
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Answer:

Explanation:

The following code is written in Java, it asks the user for the number of inputs that will be made and then the inputs. These inputs are placed into an array. Then the array is sorted and printed out to the terminal.

public static void sortArrayList() {

           ArrayList<Integer> sortedList = new ArrayList();

           Scanner input = new Scanner(System.in);

           System.out.println("Enter number of digits in Array");

           int numberOfInputs = input.nextInt();

           for (int i = 0; i < numberOfInputs; i++) {

                   System.out.println("Enter a number");

                   sortedList.add(input.nextInt());

           }

           int n = sortedList.size();

           for (int i = 0; i < n; i++)

               for (int j = 0; j < n-i-1; j++)

                   if (sortedList.get(j) > sortedList.get(j + 1))

                   {

                       // swap arr[j+1] and arr[j]

                       int temp = sortedList.get(j);

                       sortedList.set(j, sortedList.get(j + 1));

                       sortedList.set(j + 1, temp);

                   }

           for (int x : sortedList) {

               System.out.println(x);

           }

       }

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