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Airida [17]
3 years ago
13

Which type of electromagnetic wave do cell phones send and receive.

Computers and Technology
2 answers:
iris [78.8K]3 years ago
6 0

Answer:

D. Microwaves

Explanation:

Did the test !!

Slav-nsk [51]3 years ago
4 0
?? it should be radio waves but i guess the next best thing is microwaves
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The______for our newest game keeps changing as we develop our concept and refine our goals.
antiseptic1488 [7]
I think d is the best here
6 0
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Once Raul selects a technology solution, he has completed the process. <br> a. True<br> b. False
romanna [79]
The answer is true because choosing a technology solution is the last step
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3 years ago
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The average pH of citrus fruits is 2.2, and this value has been stored in the variable avg_citrus_pH . Provide a statement to di
olasank [31]

Answer:

The statement in Python is:

print("The average pH of citrus fruits is ",avg_citrus_pH)

Java

System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);

C++

cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;

Explanation:

The programming language is not stated; so, I answered the question in 3 languages (Python, Java and C++)

Assume that avg_citrus_pH has been declared and initialized; all you need to do is invoke a print statement and then append the variable

In Python, use print()

In c++, use cout<<

In Java, use System.out.print()

So, the statements are:

Python:

print("The average pH of citrus fruits is ",avg_citrus_pH)

Java

System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);

C++

cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;

8 0
3 years ago
Write a program that reads numbers from scanf (keyboard) and then sums them, stopping when 0 has been entered. Construct three v
almond37 [142]

Answer:

For loop Version:

#include <stdio.h>

int main()

{

   int number, sum = 0;

   printf("Enter a positive integer: ");

   scanf("%d", &number);

   

   for (int i = 0; i <= number; i++) {

       if(number == 0)

           break;

       sum += number;

       

       printf("Enter a positive integer: ");

       scanf("%d", &number);

   }

   printf("Sum is: %d", sum);

   return 0;

}

- - - - -

While Loop Version:

#include <stdio.h>

int main()

{

   int number, sum = 0, i = 0;

   printf("Enter a positive integer: ");

   scanf("%d", &number);

   

   while (number != 0) {

       sum += number;

       

       printf("Enter a positive integer: ");

       scanf("%d", &number);

   }

   printf("Sum is: %d", sum);

   return 0;

}

Do-while Loop Version:

#include <stdio.h>

int main()

{

   int number, sum = 0, i = 0;

   

   do {

       printf("Enter a positive integer: ");

       scanf("%d", &number);

       

       sum += number;

       

   } while (number != 0);

   printf("Sum is: %d", sum);

   return 0;

}

Explanation:

- Initialize the variables

- Ask the user for the numbers until the user enters 0

-  Calculate and print the sum

4 0
3 years ago
1. Write programming code in C++ for school-based grading system. The program should accept the Subject and the number of studen
satela [25.4K]

In this program, I am using the school-based grading system and the program should accept the subject and the number of students.

Program approach:-

  • Using the necessary header file.
  • Using the standard I/O namespace function.
  • Define the main function.
  • Declare the variable.
  • Display enter obtain marks in 5 subjects.
  • Return the value.

Program:-

//header file

#include<iostream>

//using namespace

using namespace std;

//main method

int main()

{

//declare variable

  int j;

  float mark, sum=0, a;

//display enter obtain marks in 5 subjects

  cout<<"Enter Marks obtained in 5 Subjects: ";

  for(j=0; j<5; j++)

  {

      cin>>mark;

      sum = sum+mark;

  }

  a = sum/5;

//display grade

  cout<<"\nGrade = ";

  if(a>=91 && a<=100)

//display a1

      cout<<"a1";

  else if(a>=81 && a<91)

//display a2

      cout<<"a2";

  else if(a>=71 && a<81)

      cout<<"b1";

  else if(a>=61 && a<71)

      cout<<"b2";

  else if(a>=51 && a<61)

//display c1

      cout<<"c1";

  else if(a>=41 && a<51)

//display c2

      cout<<"c2";

  else if(a>=33 && a<41)

//display d

      cout<<"d";

  else if(a>=21 && a<33)

//display e1

      cout<<"e1";

  else if(a>=0 && a<21)

//display e2

      cout<<"e2";

  else

//display invalid

      cout<<"Invalid!";

  cout<<endl;

//return the value

  return 0;

}

Learn more grading system

brainly.com/question/24298916

7 0
3 years ago
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