Answer:
Reading graphs: The variable plotted on the x-axis is year while the two variables plotted on y-axis are both wolves and moose.
Interpreting variables: The population of moose rose from 800 to 1550 between 1965-1972 while the population of wolves rose from 24 to 43 between 1973-1976.
inferring: The change in population of moose might cause a change in wolves population as a result of the feeding pattern of wolves, perhaps the contest between them was affected by availability of another prey which allows the predator (wolves) to feed on another prey, hence increasing the population of moose.
Conclusion: The dip in population of moose between 1974 and 1981 could be attributed to voracious feeding pattern the predator (wolves) had on the prey (moose) which inturns allows the dip in population during the above mentioned years.
Predicting: If there is a disease infection in wolves, then there would be an increase in the population of moose the next year as a result of disruption in the predator-prey contest, hence; allows one to be more populated the following year.
Explanation:
From the above assertions, it could be deduced that only when the feeding pattern of the predator (wolves) changes then the population of the prey would either be reduced or increased.
There are no statements given however a centriole is made up of microtubules triplets in a 9+0 pattern (I am unsure of what level of depth is required)
Answer:regulation of RNA processing When a eukaryotic gene is transcribed in the nucleus.
Explanation:
the primary transcript (freshly made RNA molecule) isn't yet considered a messenger RNA. ... The pre-mRNA has to go through some modifications to become a mature mRNA molecule that can leave the nucleus and be translated.
Grow food can consist of chicken,fish,meat,eggs,milk,cheese,yogurt, basically things that are full of vitamins and minerals to keep your skin hair and eyes ✨GLOWING✨‼️ have a God blessed day✝️
Answer:
Kindly check attached picture
Quantity measured is DISTANCE
Explanation:
Segment AB = measures uniform deceleration
BC = Constant speed moved by the car
CD = Uniform acceleration
During uniform deceleration: the speed of the body is reduced at a constant rate with time.
During Constant Speed, the car maintains a Velocity which does not increase or reduce at a certain time interval.
During uniform acceleration the speed of the car increases at a constant rate with time.
B) THE quantity measured by the area covered under a speed-time graph is distance :
With speed on the vertical (y-axis) and time on the horizontal (x-axis)
Area of trapezium = 0.5(AD + BC) × height
