Answer:
13 would be a prime number.
Step-by-step explanation:
Trust me :)
Answer:
1. x = 3 or x = -8
2. x = -2 or x = 10
Step-by-step explanation:
<u>1. |2x + 5| = 11</u>
2x + 5 = 11 Or 2x + 5 = -11
-5 -5 -5 -5
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2x = 6 2x = -16
/2 /2 /2 /2
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x = 3 x = -8
<u>2. 3|x - 4| + 1 = 19</u>
3|x - 4| + 1 = 19
-1 -1
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3|x - 4| = 18
/3 /3
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|x - 4| = 6
x - 4 = -6 Or x - 4 = 6
+4 +4 +4 +4
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x = -2 x = 10
The answer:
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x = (⅔)y ;
y = 3x/2.
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Given:
x + (⅓)y + x - (2/4)<span>y - x = (3/6)y ;
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</span>
Take the: x + x - x = 1x + 1x - 1x = 2x - 1x = 1x = x ;
and rewrite:
x + (⅓)y - (2/4)y = (3/6)y ;
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Note that: (2/4)y = (<span>½)y ;
and: (3/6)y = (</span><span>½)y ; so;
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Rewrite as:
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</span>x + (⅓)y - (½)y = (½)y ;
Add "(½)y" to EACH SIDE of the equation;
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x + (⅓)y - (½)y + (½)y = (½)y + (½)y ;
to get: x + (⅓)y = y ;
x = 1y - (⅓)y = (3/3) y - (1/3)y - [ (3-1)/3] y = (⅔)y ;
So: x = (<span>⅔)y ;
In terms of "y" ;
Given: </span>(⅔)y = x ; Multiply each side of the equation by "3" ;
3*[(⅔)y] = 3*x ;
to get: 2y = 3x ;
Now, divide EACH SIDE of the equation by "2" ; to isolate "y" on one side of the equation; and to solve for "y" (in terms of "x"):
2y / 2 = 3x / 2 ;
to get:
y = 3x/2 ;
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Answer:
x( x-8)(x+8)
Step-by-step explanation:
x^3 - 64x
Factor out an x
x( x^2 -64)
This is the difference of squares x^2 -8^2 which is a^2 - b^2 = (a-b)(a+b)
x( x-8)(x+8)
Answer:
25/14
Step-by-step explanation:
