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3 years ago

Which should be calculated first to solve this story problem?

Mathematics

2 answers:

Mademuasel [1]3 years ago

5 0

C is the answer ..........

OverLord2011 [107]3 years ago

4 0

B.
the total number of cups of flour in 1 batch of bread

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The blue dot is at what value on the number line? ? -16 -10

Marina CMI [18]

Answer: You need to show the number line in order to get an answer.

6 0

3 years ago

The top piece from a model of city hall is shown below.

alexandr402 [8]

Answer:

The area that she painted = 896 mm^2

Step-by-step explanation:

Given:

The given figure is a pyramid with square base.

Here we need to find the surface area of the figure that need to be painted.

Surface area of a square pyramid = (S×S) + 2×S×L square.units

Where, S = side of the base L = slant height of the pyramid.

Now we have to plug in the given values.

Here S = 14, L =25

Plug in these values into the formula

= (14*14) + 2*14*25

= 196 + 700

= 896 mm^2

The area that she painted = 896 mm^2

Hope this will helpful.

Thank you.

4 0

3 years ago

Read 2 more answers

Chang made 6 identical necklaces each having beads and a pendant. The total cost of the beads and pendants for all 6 necklaces w

son4ous [18]

Answer:

One pendant costed $3.40

Step-by-step explanation:

6 0

2 years ago

Allison bought jelly beans to share with her friends. She bought pounds of blueberry jelly beans and pounds of lemon jelly beans

Vaselesa [24]

Answer: $1\dfrac{11}{12}\text{ pounds}$

Step-by-step explanation:

The complete question is provided in the attachment.

Given, Amount blueberry jelly beans= $1\dfrac{1}{4}$ pounds

$=\dfrac{5}{4}$ pounds.

Amount lemon jelly beans = $2\dfrac{1}{3}$ pounds

$=\dfrac{7}{2}$ pounds

Total jelly beans she bought = Amount blueberry jelly beans + Amount lemon jelly beans

$=(\dfrac{5}{4}+\dfrac{7}{3})$ pounds

$=\frac{15+28}{12}\text{ pounds}\\\\=\dfrac{43}{12}\text{ pounds}$

Amount of jelly beans she gave away = $1\dfrac{2}{3}=\dfrac{5}{3}\text{ pounds}$

Amount of jelly beans she has left= Total jelly beans - Amount of jelly beans she gave away

= $\dfrac{43}{12}-\dfrac{5}{3}\\\\=\dfrac{43-20}{12}\\\\=\dfrac{23}{12}\\\\=1\dfrac{11}{12}\text{ pounds}$

She has left $1\dfrac{11}{12}\text{ pounds}$ of jelly beans.

6 0

3 years ago

Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a

dolphi86 [110]

Answer:

The required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

Step-by-step explanation:

If a polynomial has degree n and $c_1,c_2,...,c_n$ are zeroes of the polynomial, then the polynomial is defined as

$P(x)=a(x-c_1)(x-c_2)...(x-x_n)$

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

$R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)$

$R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2$

$R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2$ $[a^2-b^2=(a-b)(a+b)]$

$R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2$

$R(x)=(x^2-6x+18)(x^2-4x+4)$ $[i^2=-1]$

$R(x)=(x^2-6x+18)(x^2-4x+4)$

$R(x)=x^4-10x^3+46x^2-96x+72$

Therefore the required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

3 0

3 years ago