By using scientific notation we calculated (2.3
10⁵)(1.5 10⁴) we got 345 10⁷.
Given that,
(2.310⁵)(1.5 10⁴)
By using scientific notation
The scientific notation allows us to express extremely large or extremely small numbers by multiplying them by single-digit integers and by 10 raised to the power of the corresponding exponent. The exponent is either positive or negative depending on how big or little the number is.
Now, we calculate
(2.310⁵)=2.5100000=230000
(1.5 10⁴)=1.510000=15000
Now,
=23000015000
=3450000000
=345 10⁷
Therefore, By using scientific notation we calculated (2.310⁵)(1.5 10⁴) we got 345 10⁷.
To learn more about scientific notation visit: brainly.com/question/18073768
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Answer: 5 to the 3rd times 3 to the second times 2
Step-by-step explanation:
Answer:
The solution of the inequality is x ≤ -4. A graph of the solution should have a vertical line passing through x = -4 and be shaded to the left of x = -4
Step-by-step explanation:
-7x + 13 ≥ 41
Subtract 13 from both sides
-7x ≥ 28
Dividing both sides by the -7 changes the inequality sign and we have
x ≤ -4
Hence, the solution of the inequality is x ≤ -4 and the graph of the solution should have a vertical line passing through x = -4 and it should be shaded to the left of x = -4 indicating that only numbers less than or equal to -4 are possible solutions of the inequality.
Hope this Helps!!!
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.
Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.
Let us try it below:
Sigma notation 1:
10
<span> Σ (2i + 3)
</span>i = 3
@ i = 3
2(3) + 3
12
The first sigma notation does not have the same result, so we move on to the next.
10
<span> Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.
When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)
Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.
Ratio is 5girls:7boys with total 72 students
5+7= 12
72➗12= 6
6(5:7)= 30 girls : 42 boys
New ratio is 3:4 with 48 boys
48➗4= 12
So for girls 3x12= 36
So started with 30 girls ended with 36 girls... 6 girls joined band during the school year.
