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Alex_Xolod [135]
3 years ago
13

Just answer question, No need to explain. THANKS

Mathematics
2 answers:
sergeinik [125]3 years ago
8 0
The answer is c.

The -3 means it’s shifted to the right 3 units
The 4 means it shifted up 4 units

Olin [163]3 years ago
3 0
For this case we have the following function:
 f (x) = x ^ 2
 We have the following information:
 Horizontal translations
 
Suppose that h> 0
 To graph y = f (x-h), move the graph of h units to the right
 f (x) = (x-3) ^ 2
 Vertical translations
 
Suppose that k> 0
 To graph y = f (x) + k, move the graph of k units up.
 f (x) = (x-3) ^ 2 + 4
 Answer:
 
f (x) = (x-3) ^ 2 + 4
 
option C
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Find all of the points on the x-axis which are 6 units from the point (−1, 1).
anyanavicka [17]
All the points that are 6 units from (-1, 1) are those on the circle
  (x+1)^2 +(y-1)^2 = 36

For y=0, the two points of interest satisfy
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  (x+1)^2 = 35 . . . . . . subtract 1
  x+1 = ±√35
  x = -1±√35

The points you seek are (-1-√35, 0) and (-1+√35, 0), about (-6.916, 0) and (4.916, 0).

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The correct answer is option B

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3 years ago
Need help ASAP!!!!! I WILL GIVE THE MOST BRAINLIEST TO THE FIRST PERSON THAT ANSWERS
lys-0071 [83]

Answer:

x^2 + 10x + y^2 -4y + -7 = 0

Step-by-step explanation:

For any circle point with coordinate of center (a,b) and radius r

equation of circle is given by

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_______________________________________

Given

coordinate of center =  (-5,2)

radius = 6

thus, equation of circle can be written by substituting a and b with (-5 ,2) and r =6 as shown below

(x-a)^2 + (y-b)^2 = r^2\\(x-(-5))^2 + (y-2)^2 = 6^2\\x^2 + 10x + 25 + y^2 -4y + 4 = 36\\=>x^2 + 10x + y^2 -4y + 29 = 36\\=>x^2 + 10x + y^2 -4y + 29 -36 = 36 -36\\=>x^2 + 10x + y^2 -4y + -7 = 0

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