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3 years ago

6

Simplify. y 5 · y 3 ÷ y 2

1 answer:

Gnesinka [82]3 years ago

3 0

Y^5 x y^3 /y^2
y^8/y^2
y^4

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I need some help please I would greatly appreciate it

Mars2501 [29]

Answer:

B

Step-by-step explanation:

B is correct. Writing 16 pages every day sounds possible and desirable. This is an arithmetic sequence.

4 0

3 years ago

Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0

drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

Step-by-step explanation:

The given is,

$2x+2y+z=- 2$ .......................................(1)

$-x-2y+2z=-5$ ......................................(2)

$2x+4y+z=0$ .........................................(3)

Step:1

Equation (2) is multiplied by -1 ( Eqn(2) × -1 )

$x+2y-2z=5$ .............................(4)

Subtract the equation (1) and (4)

$2x+2y+z=- 2$

$x+2y-2z=5$

( - )

$(2x-x)+(2y-2y)+(z+2z)=(-2-5)$

$x+3z=-7$ ......................(5)

Step:2

Equation (2) is multiplied by -2 ( Eqn(2) × -2)

$2x+4y-4z=10$ ........................(6)

Subtract equation (6) and (3),

$2x+4y-4z=10$

$2x+4y+z=0$

( - )

$(2x-2x)+(4y-4y)+(-4z-z)= (10-0)$

$-5z=10$

$z = - \frac{10}{5}$

z = -2

From the equation (5),

$x+3z=-7$

$x+(3)(-2)=-7$

$x = -7+6$

x = -1

From equation (1),

$2x+2y+z=- 2$

Substitute x and z values,

$(2)(-1)+2y+(-2)=-2$

$2y - 4=2$

$2y=4-2$

$2y=2$

$y=\frac{2}{2}$

y = 1

Step:3

Check for solution,

$-x-2y+2z=-5$

Substitute x,y and z values,

$-(-1)-(2)(1)+(2)(-2)=-5$

$1-2-4=-5$

-5 = -5

Result:

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

8 0

3 years ago

Samuel bought a cement mixer for $54,205. The value of the cement mixer depreciated at a constant rate per year. The table shows

Paul [167]

The value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$

Given to us

The value of cement mixer when bought, $P$ = $ 54,205

the value of cement mixer after 1 year, $P_1$ = $ 47,158. 35

the value of cement mixer after 2 year, $P_2$ = $ 41,027. 76

To find out depreciation we can use the formula for depreciation,

$P_n= P(1-r)^n\\where,\\P_n= Value\ of\ asset\ after\ n\ year\\P= Value\ of\ asset\ when\ bought\\r= rate\ of\ depreciation\\n= number\ of\ years$

By putting the value, in the formula we get,

$P_1= P(1-r)^n\\\\47,158.35= 54,205\times (1-r)^1\\\\\dfrac{47,158.35}{54,205} = (1-r)\\\\0.87=1-r\\\\r=0.13$

Therefore, putting the value of $r$ and $P$ in depreciation formula for $t$ years we get,

$P_n= P(1-r)^n$

$f(t) = 54,205(0. 87)^{t}$

Hence, the value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$ .

To know more visit:

brainly.com/question/3023490

8 0

2 years ago

List all the factors of 16

Natasha2012 [34]

1 x 16 , 2 x 8 , 4 x 4

4 0

3 years ago

If a measured distance of 5 inches on a map respresents an actual distance of 3 miles, what is the fractional scale of the map?

OverLord2011 [107]

5 inches: 3 miles
1 inch: 0.6 miles

8 0

3 years ago