Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3
<u>Solution:</u>
We have been given two equations which are as follows:
3x - 4y = -24 ----- eqn 1
x + 4y = 8 -------- eqn 2
We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.
We rearrange eqn 2 as follows:
x + 4y = 8
x = 8 - 4y ------eqn 3
Now we substitute eqn 3 in eqn 1 as follows:
3(8 - 4y) -4y = -24
24 - 12y - 4y = -24
-16y = -48
y = 3
Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:
x = 8 - 4(3)
x = 8 - 12 = -4
Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.
Forgive if I am wrong, but I think the answer is 360 feet cubed
Answer:
x= 16 or -8
Step-by-step explanation:
absoultes
Answer:
Step-by-step explanation:
<u>Given relationships:</u>
DE = 2 AC
- Incorrect. Should be DE = 1/2 AC
DE║AC
m∠BCA = 2(m∠BED)
- Incorrect. Should be m∠BCA = m∠BED
DE = AC
- Incorrect. Should be DE = 1/2 AC
