Answer:
acute and equilateral
Step-by-step explanation:
because all the angles are given equal
Answer:
The solutions of the equation are 0 and 0.75.
Step-by-step explanation:
Given : Equation ![16x^4 - 24x^3 +9x^2 =0](https://tex.z-dn.net/?f=16x%5E4%20-%2024x%5E3%20%2B9x%5E2%20%3D0)
To find : All solutions of the equation algebraically. Use a graphing utility to verify the solutions graphically ?
Solution :
Equation ![16x^4 - 24x^3 +9x^2 =0](https://tex.z-dn.net/?f=16x%5E4%20-%2024x%5E3%20%2B9x%5E2%20%3D0)
![x^2(16x^2-24x+9)=0](https://tex.z-dn.net/?f=x%5E2%2816x%5E2-24x%2B9%29%3D0)
Either
or ![16x^2-24x+9=0](https://tex.z-dn.net/?f=16x%5E2-24x%2B9%3D0)
When
When ![16x^2-24x+9=0](https://tex.z-dn.net/?f=16x%5E2-24x%2B9%3D0)
Solve by quadratic formula, ![x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![x=\frac{-(-24)\pm\sqrt{(-24)^2-4(16)(9)}}{2(16)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-24%29%5Cpm%5Csqrt%7B%28-24%29%5E2-4%2816%29%289%29%7D%7D%7B2%2816%29%7D)
![x=\frac{24\pm\sqrt{0}}{32}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B24%5Cpm%5Csqrt%7B0%7D%7D%7B32%7D)
![x=\frac{24}{32}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B24%7D%7B32%7D)
![x=\frac{3}{4}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B3%7D%7B4%7D)
![x=0.75](https://tex.z-dn.net/?f=x%3D0.75)
The solutions of the equation are 0 and 0.75.
For verification,
In the graph where the curve cut x-axis is the solution of the equation.
Refer the attached figure below.
Answer:
12537678446.7
Step-by-step explanation:
316+178 divided by 2427 (2639 plus 26383) - 373637/282637
Answer:
B
Step-by-step explanation:
The angle at the centre is equal to the arc that subtends it , thus
∠ ABC = arc AB = 75° → B
Answer: altitude: 5 cm
Explanation:
![\sf \dfrac{1}{2} ( a + b) h = Area \ of \ trapezium](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7B2%7D%20%20%28%20a%20%2B%20b%29%20h%20%3D%20Area%20%5C%20of%20%5C%20trapezium)
[ <u>a and b are bases, h is the altitude</u> ]
Here given:
Solve for altitude:
![\sf \rightarrow \sf \dfrac{1}{2} ( 6 + 8) h = 35 \ \ \ \Rightarrow \ \ \ \dfrac{1}{2} ( 14) h = 35 \ \ \ \ \Rightarrow \ \ \ \ 7 h = 35 \ \ \ \ \Rightarrow \ \ h = \dfrac{35}{7} \ = \ 5](https://tex.z-dn.net/?f=%5Csf%20%5Crightarrow%20%5Csf%20%5Cdfrac%7B1%7D%7B2%7D%20%20%28%206%20%2B%208%29%20h%20%3D%2035%20%20%5C%20%5C%20%20%5C%20%20%5CRightarrow%20%20%5C%20%5C%20%5C%20%5Cdfrac%7B1%7D%7B2%7D%20%20%28%2014%29%20h%20%3D%2035%20%5C%20%5C%20%5C%20%5C%20%5CRightarrow%20%20%20%5C%20%5C%20%5C%20%20%5C%207%20h%20%3D%2035%20%5C%20%5C%20%5C%20%5C%20%20%5CRightarrow%20%5C%20%5C%20%20%20h%20%3D%20%5Cdfrac%7B35%7D%7B7%7D%20%5C%20%20%20%3D%20%20%5C%20%205)