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Serjik [45]
4 years ago
14

Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m

n Superscript negative 2 Baseline EndFraction? Assume m not-equals 0, n not-equals 0.
StartFraction m Superscript 5 Baseline Over 162 n EndFraction
StartFraction 1 Over 2 m cubed n EndFraction
StartFraction 8 m Superscript 9 Baseline Over n Superscript 9 Baseline EndFraction
StartFraction 4 m Superscript 8 Baseline Over 3 n cubed EndFraction
Mathematics
2 answers:
Dovator [93]4 years ago
8 0

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.

egoroff_w [7]4 years ago
6 0

Answer:

D

Step-by-step explanation:

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Answer: Cada chico recibira 5.25

3 0
3 years ago
Write an equivalent expression for the 4th root of 324m^12 * the cubed root of 64k^9. Need help!
Elis [28]

Answer:

The equivalent expression to the givan expression is

\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3

Step-by-step explanation:

Given expression is 4th root of 324m^12 * the cubed root of 64k^9

The given expression can be written as

\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}

To find the equivalent expression to the given expression :

\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}

=\sqrt[4]{81\times 4m^{12}}\times\sqrt[3]{16\times 4k^9}

=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}

=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}

=(3\times \sqrt[4]{m^{12}})\times (4\times \sqrt[3]{k^9})

=(3\times \sqrt[4]{4m^{12}})\times (4\times \sqrt[3]{k^9})

=(3\times \sqrt[4]{4}\times (m^{12})^{\frac{1}{4}})\times (4\times {(k^9)^{\frac{1}{3}})

=(3\sqrt[4]{4}\times m^{\frac{12}{4}})\times (4\times k^{\frac{9}{3}})

=(3\sqrt[4]{4}\times m^3)\times (4\times k^3)

=3\sqrt[4]{4}m^3.4k^3

=12\sqrt[4]{4}m^3k^3

\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3

Therefore the equivalent expression to the given expression is

\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3

8 0
3 years ago
Which ordered pair is the best estimate for the solution of the system of equations? y=−2.5x+6.5
-Dominant- [34]
Answer:
(11/7 , 18/7)

Explanation:
The second given equation is:
y = x + 1 ............> I
The first given equation is:
y = -2.5 x + 6.5 ..............> II

Substitute with I in II and solve for x as follows:
y = -2.5 x + 6.5
x + 1 = -2.5 x + 6.5
x + 2.5 x = 6.5 - 1
3.5 x = 5.5
x = 11/7

Now, substitute with x in equation I to get y as follows:
y = x + 1
y = 11/7 + 1
y = 18/7

Hope this helps :)



4 0
4 years ago
Jeffery multiplied 7/8 by 2/3 and made the conclusion that the product of two rational numbers is rational. Is Jeffery correct?
SashulF [63]

Rational Number:

"In mathematics, a rational number is any number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q. Since q may be equal to 1, every integer is a rational number."

Answer:

7/8 x 2/3

= 14/24

=7/12

So Jefferey is correct!

3 0
3 years ago
Determine the volume of a cone to the nearest tenth, if the diameter of the base is 50.8 centimeters and the cone is 76.2 centim
Nostrana [21]

Answer:51455.4

Step-by-step explanation:

6 0
3 years ago
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