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Dennis_Churaev [7]
3 years ago
5

The graph of this system of equations is used to solve 4 x squared minus 3 x + 6 = 2 x Superscript 4 Baseline minus 9 x cubed +

2 x. StartLayout Enlarged left-brace 1st row 4 x squared minus 3 x + 6 2nd row y = 2 x Superscript 4 Baseline minus 9 x cubed + 2 x EndLayout What represents the solution set? y-intercepts of the graph x-intercepts of the graph y-coordinates of the intersection points x-coordinates of the intersection points
Mathematics
1 answer:
Andrews [41]3 years ago
6 0

Answer:

D on edulastic 2020

Step-by-step explanation:

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sveticcg [70]

Answer:

What is the area of the border of the wall?

Step-by-step explanation:

3 0
3 years ago
Please help! i'll give brainliest! no one would help me PLEASE.
Vanyuwa [196]

Answer:

m∠ABC = 42°

Step-by-step explanation:

5x + 13 + 3x + 33 = 70

8x + 46 = 70

8x = 24

x = 3

m∠ABC = 3(3) + 33 = 42

6 0
2 years ago
The math club sells candy bars an d drinks during football games. • 60 candy bars and 110 drinks will sell for $265. • 120 candy
Sedbober [7]
We can set up a system of equations to solve this. 

120b + 90d = 270
60b + 110d = 265

To cancel out b, first make the b terms equal.

60b · 2 + 110d · 2 = 265 · 2
120b + 220d = 530

Now subtract the equations.

 120b +   90d =  270
-120b + 220d =  530
---------------------------
            -130d = -260

Solve for d.

-130d/-130 = -260/-130
d = 2

Now put the value of d in one of the equations. 

60b + 110d = 265
60b + 110 · 2 = 265
60b + 220 = 265
60b + 220 - 220 = 265 - 220
60b = 45
60b/60 = 45/60
b = 0.75

Each candy bar sells for $0.75

Hope this helps! :)
7 0
3 years ago
Please help me with this homework question. No silly answers please and no bots, links, etc! I will mark brainliest to whoever g
Andre45 [30]

Answer:

T = (m × 20) + 25

(2.5 × 20) + 25 = 75

<u>75 minutes</u>

110 - 25 = 85

85 ÷ 20 = 4.25

<u>4.25 kilograms</u>

6 0
3 years ago
look at the figure shown below which step should be used to prove that point a is equidistant from points c and b
JulijaS [17]
D
is certainly wrong. You could extend the length of AD as far as you want and the two triangles (ABD and ACD) would still be congruent.

C
is wrong as well. The triangles might be similar, but they are more. They are congruent.

B
You don't have to prove that. It is given on the way the diagram is marked.

A
A is your answer. The two triangles are congruent by SAS 
3 0
3 years ago
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