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ddd [48]
3 years ago
10

You have a standard deck of cards. The deck has 52 total cards and contains 4 suits: hearts, clubs, diamonds, and spades. Each s

uit consists of cards numbered 2-10, a jack, a queen, a king, and an ace.
You select one card at random from the deck. Let A be the event that the randomly selected card is a diamond and let B be the event that the card is a king. Based on this information, answer the following questions.

What is P(A) the probability that the card is a diamond?

What is P(B) the probability that the card is a king?

What is P(A and B) the probability that the card is a diamond and a king?

What is P(A | B), the conditional probability that the card is a diamond given that it is a king?
Mathematics
1 answer:
Leokris [45]3 years ago
8 0

Answer:

A standard deck of cards has four suites: hearts, clubs, spades, diamonds. Each suite has thirteen cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen

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X^2+4x+20=12x-5<br><br> Solve this equation
Scrat [10]

Answer:

4 + (or -) 3i

Step-by-step explanation:

Hi!

Alright, so we're going to move all of the variables and constants to one side. Then, using the quadratic formula, we'll find the answer.

1. Move 12x-5 to the left side of the equation by

  a. Subtracting 12x from both sides

  b. adding 5 to both sides.

1: x^2+4x+20-12x+5

2. Group the common terms

  x^2+4x-12x+20+5 --> x^2-8x+25

3. Look at the problem. We can't factor this.

Explanation for why this isn't factorable (you can skip this)

(1) 25 is positive, so its two factors will both be either positive or negative. We're looking for a negative 8, so let's go with negative.

(2) Factors of 25: 1 & 25, 5 &5

Seeing the problem? Ya, none of the factors of 25 sum to eight. So, instead, we're going to use the quadratic formula.

4.  So, the quadratic formula: \frac{-b+-\sqrt{b^2-4ac} }{2a}

Our equation is x^2-8x+25=0

a is the constant in front of the x^2

b is the constant in front of the x

c is the term without any x values

so, a=1, b=-8, and c= 25

Into equation:

\frac{8+-\sqrt{64-4(1)(25)} }{2a}=\frac{8+-\sqrt{64-100} }{2}=\frac{8+-\sqrt{-36} }{2}

8/2 = 4

sqrt(-36) = 6i

6i/2 = 3i (remember, we still have the two in the denominator)

4 + (or -) 3i

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