Question

Which of the following are solutions to the equation below?

Answer 1

Answer:

$\large\boxed{\sf \ \ x = 3+\sqrt{11} \ \ or \ \ x = 3-\sqrt{11} \ \ }$

Step-by-step explanation:

Hello,

   $x^2-6x+9=11\\ x^2-2*3*x+3^2=11\\(x-3)^2=11\\ x-3=\sqrt{11} \ or \ x-3=-\sqrt{11}\\ x = 3+\sqrt{11} \ or \ x = 3-\sqrt{11}$

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Answer 2

Answer:

x = 3 ± sqrt(11)

Step-by-step explanation:

x^2 - 6x + 9 = 11

Recognizing  that this is a perfect square trinomial

(x-3) ^2 =11

Taking the square root of each side

sqrt((x-3) ^2) = ± sqrt(11)

x-3 =± sqrt(11)

Add 3 to each side

x = 3 ± sqrt(11)