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3 years ago

Assessment started: undefined.

Mathematics

2 answers:

VARVARA [1.3K]3 years ago

7 0

Parallel lines will always be the same distance apart

BlackZzzverrR [31]3 years ago

5 0

Parallel lines will always be the same distance apart.

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The taxi fare in a city is $3 and then $0•40 for every kilometre travelled.A taxi fare is $9.How far has the taxi travelled

Mrrafil [7]

Answer:

Step-by-step explanation: you would first subtract the 3 from 9 for a basic fee. And after you would decide 6 by .40 and you would end up traveling 15km

5 0

3 years ago

Find the solution(s) of the quadratic equation 2x2 – 3x – 35 = 0

Yuliya22 [10]

Answer: x = 5, x = -7/2

Step-by-step explanation:

2x² - 3x - 35 = 0

Step 1: Find two values whose product = 2(-35) and sum = -3: -10 & 7

Step 2: Replace the b-value of -3x with -10x + 7x:

2x² - 10x + 7x - 35 = 0

Step 3: Factor the first two terms and the second two terms:

2x(x - 5) +7(x - 5) = 0

Step 4: Write the factored form:

Notice that the parenthesis are identical. This is one of the factors. The outside values are the other factor:

Parenthesis: (x - 5)

Outside: (2x + 7)

Factored form: (x - 5)(2x + 7) = 0

Step 5: Set each factor each to zero and solve for x:

x - 5 = 0 2x + 7 = 0

x - 5 $x=-\dfrac{7}{2}$

3 0

3 years ago

F(x)=x^2 linear or exponential

marusya05 [52]

Answer:

exponential

Step-by-step explanation:

3 0

3 years ago

Jason rowed 1/3 of a mile down the river.Jane rowed 2/6 of a mile down the river. Jude rowed 2/9 of a mile down the river.What i

seraphim [82]

Answer:

8 / 9 miles

Step-by-step explanation:

Given that:

Jason's distance = 1/3 mile

Jane's distance = 2/6 miles

Jude's distance = 2/9 miles

The total miles rowed down the river by all 3 :

(1/3 + 2/6 + 2/9) miles

The L. C. M of the denominator (3, 6, 9) = 18

(6 + 6 + 4) / 18

16 / 18 miles

8 / 9 miles

4 0

3 years ago

Solve for x in the equation 2 x squared + 3 x minus 7 = x squared + 5 x + 39.

Nastasia [14]

Answer:

$\implies x=1\pm \sqrt{47}$

Step-by-step explanation:

We want to solve for x in $2x^2+3x-7=x^2+5x+39$

You need to group and combine like terms and write in standard form:

$2x^2-x^2+3x-5x-7-39=0$

$\imples x^2-2x-46=0$

By comparing to $ax^2+bx+c=0$ , we a=1,b=-2 and c=-46

The solution can be obtained using the quadratic formula.

$x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}$

We substitute the coefficients to get:

$x=\frac{--2\pm \sqrt{(-2)^2-4*1*-46} }{2*1}$

$x=\frac{2\pm \sqrt{4+4*46} }{2}$

$x=\frac{2\pm \sqrt{4*47} }{2}$

$x=\frac{2\pm2\sqrt{47} }{2}$

$\implies x=1\pm \sqrt{47}$

The last choice is correct

5 0

3 years ago

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