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Readme [11.4K]
4 years ago
12

Ellen was learning to swim. The first day of lessons, she swam 1/6 of a lap. On the second day, she swam 1/3 of a lap. On the th

ird day, she swam 4/6 of a lap. On which day did Ellen swim the farthest?
Mathematics
1 answer:
Jlenok [28]4 years ago
4 0

Answer:

The answer to your question is the third day

Step-by-step explanation:

Data

First day   1/6

Second day  1/3

Third day    4/6

Process

1.- Convert all the fractions to the same denominator. I'll convert them to 6

First day            1/6

Second day      2/6

Third day           4/6

2.- Compare the numerators

                        4 > 2 > 1

3.- Conclusion

She swan the farthest the third day

You might be interested in
2(2x - 4) = 4(x - 2)<br> What is the solution
galben [10]

Answer: 0

Step-by-step explanation:

2(2x-4)=4(x-2) - Start off by diong distributive property on both sides

4x-8=4x-8 - Add 8 to both sides toget rid of it

4x=4x - Divide both sides by 4

0 = 0 - The 2 equations are equal therefore the answer is 0

Hope this helps!

4 0
3 years ago
Round 4265 to the nearest hundred
Hatshy [7]
Answer:

4300

Explanation:

The given number is 4265

This can be written as:

4 thousand

2 hundred

6 tens

5 units

Therefore, since 6 is greater than 5, change 6 and 5 to zero and 1 to 2.

4265 rounded to the nearest hundred becomes 4300

4 0
1 year ago
GUYS PLS HELP MEEEE I REALLY NEED HELP
PilotLPTM [1.2K]

Answer:

x = 22.45

Step-by-step explanation:

Have a good day :)

6 0
3 years ago
Can someone help me with this question it is so confusing
zmey [24]

we know it takes 20lbs of Olive to make 3 liters of oil, we also know that the orchard for a whole year gets 3000 lbs, how much oil is there in those 3000 lbs for the year?

\bf \begin{array}{ccll} \stackrel{olive}{lbs}&\stackrel{olive~oil}{liters}\\ \cline{1-2} 20&3\\ 3000&x \end{array}\implies \cfrac{20}{3000}=\cfrac{3}{x}\implies \cfrac{1}{150}=\cfrac{3}{x}\implies x= 450

3 0
4 years ago
Find the measure indicated. Assume that the lines which appear to be tangent are tangent. PART 3
ludmilkaskok [199]

I'll do problems 13 and 14 to get you started.

=====================================================

Problem 13

<h3>Answer:  32 degrees</h3>

-----------------------

Explanation:

Refer to the diagram below for problem 13. Since BD is a tangent of the circle, this means angle ABD is 90 degrees, and furthermore x+y = 90. This solves to y = 90-x.

If we focus on triangle ABC, then we can add the interior angles and set the sum equal to 180

A+B+C = 180

z+y+y = 180

z+2y = 180

z+2(90-x) = 180 .... plug in y = 90-x

z+180-2x = 180

z-2x = 180-180

z-2x = 0

z = 2x

We'll use this later.

Now move onto triangle ABD. This is a right triangle due to angle ABD being 90 degrees. The acute angles z and 26 are complementary, meaning they add to 90. So,

z+26 = 90

z = 90-26

z = 64

Now plug this into z = 2x and solve for x

z = 2x

64 = 2x

2x = 64

x = 64/2

x = 32

=====================================================

Problem 14

<h3>Answer: 31 degrees</h3>

-----------------------

Explanation:

Refer to the image shown below for problem 14. Like before, I've added various labels to it to help find the angle we're after (the red angle x).

Note how I've drawn a dashed line from point A to point D. This splits up quadrilateral ABCD into two triangles ABD and ACD. These triangles can be shown to be congruent using the HL (hypotenuse leg) theorem.

The congruent triangles also implies that angle DBC and angle BCD are the same measure (both are shown in green as the variable y).

Focus on triangle BCD. It has interior angles of: y, y and 62. Add them up, set the sum equal to 180.

y+y+62 = 180

2y+62 = 180

2y = 180-62

2y = 118

y = 118/2

y = 59

As the image attachment mentions, the angles x and y add to 90 degrees. This is because angle ABD is 90 degrees, due to segment BD being tangent to the circle. So x+y = 90 leads to x = 90-y, and therefore,

x = 90-y

x = 90-59

x = 31

Side note: it is not a coincidence that we ended up with half of the value of 62.

3 0
3 years ago
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