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ANEK [815]
3 years ago
13

Elena makes banana bread and nut bread to sell at the market. A loaf of banana bread requires 2 cups of flour and 2 eggs. A loaf

of nut bread takes 3 cups of flour and 1 egg. Elena has 12 cups flour and 8 eggs on hand. If she makes $1.50 profit per loaf of banana bread and $2 per loaf of nut bread, how many loaves of banana bread and nut bread could she make that will maximize her profit? A. Elena could make 0 loaves of banana bread and 4 loaves of nut bread to maximize her profit. B. Elena could make 2 loaves of banana bread and 3 loaves of nut bread to maximize her profit. C. Elena could make 3 loaves of banana bread and 2 loaves of nut bread to maximize her profit. D. Elena could make 1 loaf of banana bread and 5 loaves of nut bread to maxim

Mathematics
2 answers:
Rainbow [258]3 years ago
8 0

The answer is Elena could make 3 loaves of banana bread and 2 loaves of nut bread to maximize her profit

algol [13]3 years ago
3 0

Answer:

The correct answer is option C

Step-by-step explanation:

Let the number of loaves of banana bread be = x

Let the number of loaves of nut bread be = y

As given, a loaf of banana bread requires 2 cups of flour and 2 eggs, then x loaves will need 2x cups of flour and 2x eggs. Similarly, a loaf of nut bread needs 3 cups of flour and 1 egg, then y loaves will need 3y cups of flour and y eggs.

Also give is , Elena has 12 cups flour and 8 eggs then equations with respect to flour and eggs become :

2x+3y≤12      (flour)

2x+y≤8         (eggs)

Its stated that if Elena makes $1.50 profit per loaf of banana bread and $2 per loaf of nut bread, so she makes a total profit of 1.50x+2y    .... (a)

Now, to solve the maximum profit we will make a graph. Please find attached the graph. The maximum profit is calculated at point (3,2)

Now putting x as 3 and y as 2 in equation (a)

1.50*3+2*2 = 4.5+4 = $8.5

Hence, Elena could make 3 loaves of banana bread and 2 loaves of nut bread to maximize her profit.

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Answer:

14.63% probability that a student scores between 82 and 90

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 72.3, \sigma = 8.9

What is the probability that a student scores between 82 and 90?

This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So

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Z = \frac{90 - 73.9}{8.9}

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Z = 0.91 has a pvalue of 0.8186

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Answer and working out attached. Hope this helps

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Answer:

ok thanks bro lol thanks

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