Answer:
(a)0,2 1,-1 2,-4 3,-7 (b) yes
Answer:
an=8n−14
Step-by-step explanation:
for an AP
where
a
1
=
the first term
d
=
the common difference
then we have
a
1
,
(
a
1
+
d
)
,
(
a
1
+
2
d
)
,
...
,
a
1
+
(
(
n
−
1
)
d
)
,
.
.
we are given the third term
10
=
a
1
+
2
d
−
−
(
1
)
and the fifth term
26
=
a
1
+
4
d
−
−
(
2
)
subtract
(
2
)
−
(
1
)
16
=
2
d
⇒
d
=
8
sub into
(
1
)
10
=
a
1
+
2
×
8
⇒
a
1
=
−
6
so the nth term
a
n
=
a
+
(
n
−
1
)
will be
a
n
=
−
6
+
8
(
n
−
1
)
a
n
=
8
n
−
14
12 • 5/2
Reduce numbers with GCF (2)
6 • 5
Multiply numbers
30
x | y
5 2
6 5
7 8
8 11
yes, because each x value has exactly one 7 value
