Question

Beau has decided to use the method of elimination to solve the system of equations as shown below.

Answer 1

Answer:

Step-by-step explanation:

The given equations are:

$2x+3y=15$                     (1)

and $x-3y=3$                 (2)

Now, simply adding equation (1) and equation (2), we get

$2x+3y+x-3y=15+3$

$3x=18$

$x=6$

Now, substituting the value of x=6 in equation (2). we get

$6-3y=3$

$6-3=3y$

$3=3y$

$y=1$

Thus, the values of x and y are 6 and 1 respectively.

In order to solve the system of solution, beau can see that in both  the given equations, coefficient of y is same and is with opposite sign, thus simply adding both the equations will eliminate y and she will get the value of x and then substituting the value of x in any of the equations, she can get the value of y. With this, she can get closer to the solution.