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Annette [7]
3 years ago
6

I'll give brainliest for the first one who can answer ( Just for Fun ) What is... 64÷2+0×2

Mathematics
2 answers:
zysi [14]3 years ago
5 0

Answer:

=32

Step-by-step explanation:

64÷2+0×2

32+0x2

32+0

=32

svlad2 [7]3 years ago
4 0

Answer:

64?

Step-by-step explanation:

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Consider the function represented by the equation 6q = 3s - 9. Write the equation in function notation, where q is the independe
Llana [10]
Q = 3s - 9/6
q = 3(s - 3)/6
q = s - 3/2

6q + 9 = 3s
6q + 9/3 = s
3(2q + 3)/3 = s
2q + 3 = s
s = 2q + 3
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3 years ago
Is 12.54 greater than 12.539?
Damm [24]

Answer:

yes

Step-by-step explanation:

12.54

>

12.53

reason why is because of the 4>5

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3 years ago
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Pe lingNeed 2 yards of fabric for a craft project she has 3 feet already how many inches of fabric does she need still need
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36 inches

Step-by-step explanation:

12 inches equals 1 foot

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3 0
3 years ago
Please Help! 66 points and brainliest!
yanalaym [24]

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No because opinions and social values may lead to bis

Step-by-step explanation:

4 0
3 years ago
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A company compiles data on a variety of issues in education. In 2004 the company reported that the national college​ freshman-to
nasty-shy [4]

Answer:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

Step-by-step explanation:

For this case we know that we have a sample of n = 500 students and we have a percentage of expected return for their sophomore years given 66% and on fraction would be 0.66 and we are interested on the distribution for the population proportion p.

We want to know if we can apply the normal approximation, so we need to check 3 conditions:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

And we can use the empirical rule to describe the distribution of percentages.

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

8 0
3 years ago
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