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Ymorist [56]
3 years ago
15

Which Is a factor of 6x^2+x-7

Mathematics
2 answers:
jasenka [17]3 years ago
5 0
The factor by grouping is (x-1)(6x+7)
Gnom [1K]3 years ago
4 0
6x^2 + x - 7
(x - 1)(6x + 7) are the two factors.
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Write an absolute value inequality that has 3 and -6 as two of its solutions
GenaCL600 [577]

Answer:it can be 3P = -6

Step-by-step explanation:

p is equal to 3*6 so 3p=-6

7 0
4 years ago
a student found the slope of a line that passes through the point (-3,-10) and (5,-7) to be 3/8 what mistake did he make
In-s [12.5K]
The student didn't make any mistake. The slope of the line between those points is 3/8.

3 0
4 years ago
Can someone please answer the highlighted questions? thanks!
raketka [301]

Answer:

28 = 14 + x,  51 = 38 + x

Step-by-step explanation:

I got both sums because the last part says "is 28" and "is fifty-one," signaling that they each take up one side of the equation. Sum means add (so a + sign) and more than also means add (in this case). X just stands for the numbers not given.

4 0
4 years ago
Read 2 more answers
State whether the data described below are discrete or continuous, and explain why The durations of movies in minutes A Choose t
yKpoI14uk [10]

Answer:

D. The data are discrete because the data can only take on specific values.

Step-by-step explanation:

<u>Continuous variables</u> are variables that can take on any value in an interval. Examples of continuous variables are length, time, etc.

<u>Discrete variables</u> on the other hand are variables that can only take on specific values.

The durations of movies in minutes<u> can only take on integer values from 0 to 60.</u> Therefore, it is a discrete data.

The correct option is D.

4 0
3 years ago
What is 8 3/4 - 7 1/2
lara31 [8.8K]

let's firstly convert the mixed fractions to improper fractions and then subtract, bearing in mind that the LCD of 4 and 2 is 4.

\bf \stackrel{mixed}{8\frac{3}{4}}\implies \cfrac{8\cdot 4+3}{8}\implies \stackrel{improper}{\cfrac{35}{4}}~\hfill \stackrel{mixed}{7\frac{1}{2}}\implies \cfrac{7\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{15}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{35}{4}-\cfrac{15}{2}\implies \stackrel{\textit{using the LCD of 4}}{\cfrac{(1)35~~-~~(2)15}{4}}\implies \cfrac{35-30}{4}\implies \cfrac{5}{4}

6 0
3 years ago
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