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Ymorist [56]
3 years ago
15

Which Is a factor of 6x^2+x-7

Mathematics
2 answers:
jasenka [17]3 years ago
5 0
The factor by grouping is (x-1)(6x+7)
Gnom [1K]3 years ago
4 0
6x^2 + x - 7
(x - 1)(6x + 7) are the two factors.
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I WILL GIVE BRAINLIEST!!!! ASAP!!! A reflection over the x-axis maps △ABC to △A′B′C′. Do the preimage and image have the same si
Rudiy27

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yes because it just reflected, the shape didn't get smaller or bigger. it stayed the same

5 0
3 years ago
(16 points) (geometry) i need help plzzzzz
Rom4ik [11]

Answer:sry I don’t get tht type of math if I did I would of helped u sry :( but I hope u have a wonderful Christmas break ❄️

Step-by-step explanation:

6 0
3 years ago
Reduce to simplest form<br> +
kifflom [539]

Answer:

?

Step-by-step explanation:

What is the question?

7 0
3 years ago
A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie. Among the 500 ​respondents,
RoseWind [281]

Answer:

The statement that​ "the margin of error was given as \pm5 percentage​ points" means that the population proportion is estimated to be with a certain level of confidence, within the interval \hat{p} \pm 0.05 ; where \hat{p}[tex] is the sample's proportion. The correct answer is C. The statement indicates that the interval [tex]0.14\pm0.05 is likely to contain the true population percentage of people that prefer chocolate pie.

Step-by-step explanation:

The margin of error for proportions is given by the following formula:

z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}

Where:

z_{\alpha /2} is the critical value that corresponds to the confidence level; the confidence level being 1-\alpha,

\hat{p} is the sample's proportion of successes,

n is the size of the sample.

In this exercise we have that \hat{p}=0.14 and that the margin of error is 0.05.

Therefore if we replace in the formula to calculate the confidence interval we get:

\hat{p}\pm 0.05=0.14\pm0.05=(0.09, 0.19)

Which means that the true population proportion is estimated to be, with a certain confidence level, within the interval (0.09, 0.19).

7 0
3 years ago
There are two colored marbles and one white marble in a box. Julie mixes the marbles and then Sam draws two marbles at random wi
tino4ka555 [31]
At first there are three marbles for Sam to pick from. the possibility of drawing a colored marble is 2/3. if Sam picks one of the colored marbles, the possibility of therefore (if he'd drawn the colored marble) drawing the second colored marble is 1/2. for the possibility of those happening consequently, we have to multiply the possibilities. 2/3 * 1/2 is 2/6 is 1/3. which means Sam wins in 33.333...% cases. Julie has a better chance of winning.

adding a white marble would change the possibilities to 1/2 and 1/3 consequently, meaning Sam wins in 1/2 * 1/3 = 1/6 = 16.7% cases, which is even less fair.

adding a colored marble would change the possibilities to 3/4 and 2/3 consequently, meaning Sam wins in 3/4 * 2/3 = 6/12 = 50% cases, which finally makes the game fair.
6 0
2 years ago
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