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baherus [9]
3 years ago
9

Determine whether the graph table or equation represents a linear nonlinear function.

Mathematics
1 answer:
Fofino [41]3 years ago
3 0

Answer:

nonlinear

Step-by-step explanation:

x(x + 3) =  {x}^{2}  + 3  \\ \: it \: will \: be \: a \: parabola \: because \: of \: the \:  {x}^{2}

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What is the slope of the line in the graph?
Viktor [21]

Answer:

The slope of the line in the graph is 1.

Step-by-step explanation:

Slope is determined by rise over run. Meaning that the number of units the slope goes up/down divided by the number of units the slope goes to the left/right is the slope. The rise is one, and the run is one. 1 over 1 equals 1.

4 0
3 years ago
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The qoutient of any two nonzero integers is an integer. True or false
guapka [62]
False.

Here is a counterexample.

3/4= 0.75

3 and 4 are both integers but the quotient is 0.75 which is not an integer. 0.75 is a rational number.
8 0
3 years ago
In circle O, RT and SU are diameters. If m = m, what is m? 47° 52° 64° 87°
vlada-n [284]
From the given figure, it can be seen that 13x = 15x - 8 because they are vertical angles and thus are equal.

13x = 15x - 8
15x - 13x = 8
2x = 8
x = 8/2 = 4

Thus, 15x - 8 = 15(4) - 8 = 60 - 8 = 52.

RT is a diameter, which means that mRT = 180

mRV + mVU + 52 = 180

mRV + mVU = 180 - 52 = 128

Now, given that mRV = mVU,

Thus, 2mVU = 128

Therefore, mVU = 128 / 2 = 64°
8 0
3 years ago
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A reflection across the x-axis keeps the x-coordinate the same but flips the y-coordinate. What do you think a reflection across
Studentka2010 [4]

Answer: A reflection across the x-axis keeps the x-coordinates the same but flips the signs of the y-coordinates. So, it should be the opposite for a reflection across the y-axis. The y-coordinates remain the same, but the signs of the x-coordinates change.

Step-by-step explanation

I copy and pasted the answer

8 0
3 years ago
Please answer the image below
nikklg [1K]

Answer:

<h2>301.593</h2><h2 />

Step-by-step explanation:

surface area = 2πrh + 2πr²

where r = 4 km radius

           h = 8 km

<u>plugin values into the formula</u>

surface area = 2πrh + 2πr²

                     = 2π (4) 8  +  2π (4)²

                     = 201.062  +  100.531

                     = 301.593 km²

7 0
3 years ago
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