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2 years ago

Name 3 numbers that are multiples of 4 and 8

Mathematics

1 answer:

motikmotik2 years ago

5 0

16, 24, 32
and it goes on, and on.

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60 sixth graders 40% of the sixth graders will attend.

nika2105 [10]

I don't see a question here, but I think your asking how many sixth graders will attend. The answer is 24.

4 0

2 years ago

Write an equation that represents the line that passes through the points (5,4) and (-5,0)

Assoli18 [71]

Slope = (0 - 4)/(-5-5) = -4/-10 = 2/5

y = mx + b
4 = (2/5) (5) + b
4 = 2 +b
b = 2

equation

y = 2/5x + 2

7 0

2 years ago

saw5 [17]

Answer:

$280

Step-by-step explanation:

Sell 24 pieces in 3 hours, so 8 pieces in 1 hour

in 7 hours 8*7 = 56 pieces, each for $5

56 piece cost 5^56 = $280

7 0

1 year ago

Multiply find the partial products (what goes in the question mark?)<br><br> 6.4<br> x 7.8<br> 0. ??

tester [92]

Answer:

For the problem 35 x 7, the partial products would be: 7 x 30 and 7 x 5.

Step-by-step explanation:

3 0

2 years ago

Use the quadratic formula to solve for the roots in the following equation. 4x 2 + 5x + 2 = 2x 2 + 7x – 1

Natali5045456 [20]

Answer:

So, The roots are $x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

Step-by-step explanation:

$4x^2 + 5x + 2 = 2x^2 + 7x - 1$

We need to solve the equation to find the roots using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Rearranging the above equation:

$4x^2 -2x^2+ 5x-7x + 2+1 =0$

$2x^2 -2x + 3 =0$

Where a =2 , b=-2 and c =3 Putting values in quadratic equation and solving:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-2)\pm\sqrt{(-2)^2-4(2)(3)}}{2(2)}\\x=\frac{2\pm\sqrt{4-24}}{4}\\x=\frac{2\pm\sqrt{-20}}{4}\\\sqrt{-20} \,\,can\,\,be\,\, written\,\, as\,\, 2\sqrt{-5}\\ x=\frac{2\pm2\sqrt{-5}}{4}\\x=\frac{2+2\sqrt{-5}}{4} \,\, and \,\, x=\frac{2-2\sqrt{-5}}{4}\\x=\frac{2(1+\sqrt{-5})}{4} \,\, and \,\, x=\frac{2(1-\sqrt{-5})}{4}\\ x=\frac{1+\sqrt{-5}}{2} \,\, and \,\, x=\frac{1-\sqrt{-5}}{2}\\As \,\,we\,\, know\,\, \sqrt{-1} = i \\$

$x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

So, The roots are $x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

6 0

2 years ago