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3 years ago

Name 3 numbers that are multiples of 4 and 8

Mathematics

1 answer:

motikmotik3 years ago

5 0

16, 24, 32
and it goes on, and on.

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The value of the 6 in 24.695 is 10 times the value of the 6 in 16.45 is this true?

olganol [36]

This is not true....

3 0

3 years ago

Which expression is not equivalent to 6^3/6^6

vovangra [49]

Answer:

Step-by-step explanation:

The answer is C

8 0

3 years ago

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If a side of the field is 9/10 mile and 1/2 mile what is the length of the field

Katyanochek1 [597]

Answer:

The field is 1 and 4/10 mile long.

Step-by-step explanation:

If I understand the question:

(1/2) + (9/10) =

(5/10) + (9/10) = (14/10)

(14/10) is 1 and 4/10

The field is 1 and 4/10 mile long.

4 0

2 years ago

The equations 2 x minus y = negative 2, 3 x + 2 y = 5, 4 x minus y = 2, and 22 x + 10 y = 7 are shown on the graph below. On a c

KiRa [710]

Answer:

The correct answer is First option:

$22x+10y=7\\ 2x-y=-2$

Step-by-step explanation:

We are given 4 equations:

$22x+10y=7\\ 2x-y=-2\\3x+2y=5\ and\ \\4x-y=2$

Let us solve the first two:

$22x+10y=7...... (1)\\ 2x-y=-2 ...... (2)$

Multiplying (2) with 10 and adding to (1):

$22x+20x=7-20\\\Rightarrow 42x=-12\\\Rightarrow x = -0.2857 \approx -0.3$

So, approximately, value of x is -0.3.

Putting value of x in (2):

$2 \times -0.3 - y =-2\\\Rightarrow y = -0.6+2\\\Rightarrow y = 1.4$

value of x is approximately -0.3 so y is approximately 1.4.

So, the solution is $\approx$ (–0.3, 1.4)

The correct answer is First option:

$22x+10y=7\\ 2x-y=-2$

The above two equations have a solution approximately (–0.3, 1.4).

3 0

3 years ago

Read 2 more answers

ivolga24 [154]

Given:

Two jugs are similar. The smaller jug has radius 4 cm and the bigger jug has radius 6 cm and surface area 125 cm².

To find:

The area of the smaller jug.

Solution:

If two figures are similar, then the ratio of their areas is proportional to the square of the corresponding sides of the figures.

Two jugs are similar. So,

$\dfrac{\text{Area of smaller jug}}{\text{Area of bigger jug}}=\dfrac{(\text{Radius of smaller jug})^2}{(\text{Radius of bigger jug})^2}$

$\dfrac{\text{Area of smaller jug}}{125}=\dfrac{(4)^2}{(6)^2}$

$\dfrac{\text{Area of smaller jug}}{125}=\dfrac{16}{36}$

$\text{Area of smaller jug}=\dfrac{4}{9}\times 125$

$\text{Area of smaller jug}\approx 55.56$

Therefore, the area of the smaller jug is about 55.56 cm².

6 0

3 years ago

Read 2 more answers