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Mashutka [201]
3 years ago
12

What is an algebraic expression to represent the perimeter of a rectangle with a width of x+5 and a length of 3x+10?

Mathematics
1 answer:
Sveta_85 [38]3 years ago
5 0
We know that the area of a rectangle is equal to the width multiplied by the length. So in this case the algebraic expression is (x+5)*(3x+10). You get 3x^2 +10x +15x +50= 3x^2 +25x +50.
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How to solve inequalities​
Ulleksa [173]

Answer:

Step 1 Eliminate fractions by multiplying all terms by the least common denominator of all fractions.

Step 2 Simplify by combining like terms on each side of the inequality.

Step 3 Add or subtract quantities to obtain the unknown on one side and the numbers on the other.

Step 4 Divide each term of the inequality by the coefficient of the unknown. If the coefficient is positive, the inequality will remain the same. If the coefficient is negative, the inequality will be reversed.

Step 5 Check your answer.

3 0
3 years ago
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Alex has 520 yards of fencing to enclose a rectangular area.
Pavlova-9 [17]
<span>Perimeter =2w+2L= 520.
We can solve this by understanding that the area is maximized by a square
Therefore L=w.

p=2w+2w=520=4w
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3 years ago
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musickatia [10]

The correct answer is C. They are going down by 3.

4 0
3 years ago
Graph h(x)=0.5(x+2)^2 -4 by following these steps:
Goshia [24]

Answer:

Step 1: Identify a, h, and k.

a=0.5, h= -2, k= -4

Step 3: The axis of symmetry is the line x= -2

Step 4: h(-4)= -2 h(-6)= 4

The graph should have points plotted at (-6, 4), (-4, -2), (-2, -4), (0, -2), and (2, 4)

Step-by-step explanation: The answers were already there, just here to repeat for others who are confused.

4 0
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HELLLP ASAP FIRST PERSON WITH CORRECT ANSWER WILL RECEIVE BRAINLIEST
Nikitich [7]
Rotating Q 180 degrees using the center P has the same effect as reflecting Q over the Line M
Step-by-step explanation:
Rotating Q 180 degrees using the center P has the same effect as reflecting Q over the Line M and this is because Lines L and M are perpendicular lines ( i.e. lines that meet a right angle ( 90° ).
Hence rotating Q 180 degrees form the center will be similar to reflecting Q over any of the perpendicular lines
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3 years ago
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