All categories

4 years ago

Simplify the expression where possible. (x³y²)⁴

Mathematics

1 answer:

Karolina [17]4 years ago

5 0

Answer:

x^12y^8

Step-by-step explanation:

(x^3y^2)^4 = (x^3)^4 × (y^2)^4

=x^12y^8

You might be interested in

Write an equation perpendicular to the line 6x+12y=24 and passing through (4,0)

noname [10]

Y = 2x - 8 is perpendicular to 6x+12y=24 and passes through (4,0)

6 0

3 years ago

Does anyone know the answers to these questions

notsponge [240]

Which questions. There is no pic

8 0

3 years ago

I need help with this!!

leva [86]

Answer:

Step-by-step explanation:

5 0

3 years ago

Could I get some help PLEASE!!

kati45 [8]

Not similar, since the ratio of corespondent side is not constant
suppose ∆PRQ ~ ∆MRN, then RN/RP = RM/RQ but the reality contradict

4 0

3 years ago

Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi

adoni [48]

Answer:

$r = 4$

The center is:

(2, -4)

Step-by-step explanation:

We have the following equation

$x^2 - 4x + y^2 + 8y = -4$

The general equation of a circle has the following form

$(x-h)^2 + (y-k)^2 = r^2$

Where r is the radius and the point (h, k) is the center of the circle

To transform the given equation in the general equation of a circumference we must use the method of square completions

Step 1

$(x^2 - 4x) + (y^2 + 8y) = -4$

Step 2

Add and subtract $(\frac{b}{2})^2$ For an equation of the form

$ax^2 +bx +c$

$(x^2 - 4x +4)-4 + (y^2 + 8y +16) -16= -4$

Step 3 Factor the expressions within the parentheses

$(x-2)^2-4 + (y+4)^2 -16= -4$

Step 4 Simplify

$(x-2)^2 + (y+4)^2= -4+16+4$

$(x-2)^2 + (y+4)^2= 4^2$

Finally

$r = 4$

The center is:

(2, -4)

7 0

3 years ago