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Snezhnost [94]
4 years ago
11

*help please* What is the amplitude of the function graphed?

Mathematics
2 answers:
PIT_PIT [208]4 years ago
8 0
No wouldn’t it be 4 cuz u take the upper amp plus lower amp divide by two and get 2
Vladimir [108]4 years ago
7 0

Answer:

i think -1

Step-by-step explanation:

bc if u look at the picture

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For the function given state the period f(t) =6sin(3t-pi/6)-1
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\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\&#10;% function transformations for trigonometric functions&#10;\begin{array}{rllll}&#10;% left side templates&#10;f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\&#10;f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}&#10;&#10;\end{array}

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks}\\&#10;\quad \textit{horizontally by amplitude } |{{  A}}|\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{function period or frequency}\\&#10;\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\&#10;\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)&#10;\end{array}


now, with that template in mind, let's take a peek at yours

\bf \begin{array}{lllcclll}&#10;f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\&#10;&\uparrow &\uparrow &\uparrow &\uparrow \\&#10;&A&B&C&D&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}
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I need help on the third question.
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