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Dmitrij [34]
3 years ago
5

Kyle and josh have a total of 64 CDs. Kyle has 12 mote than josh. How many CDs does each boy have?

Mathematics
1 answer:
Alecsey [184]3 years ago
5 0
26 for Josh and 5th for kyle
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A deep sea diving bell is being lowered at a constant rate. After 10 ​minutes, the bell is at a depth of 600 ft. After 40 minute
Degger [83]
<h2>Average rate of lowering per​ minute = 36.67 ft/min</h2>

Step-by-step explanation:

After 10 ​minutes, the bell is at a depth of 600 ft

After 10 minutes

                   Depth of bell = 600 ft

After 40 minutes the bell is at a depth of 1,700 ft.

After 40 minutes

                   Depth of bell = 1700 ft

Time gap = 40 - 10 = 30 minutes

Depth fallen = 1700 - 600 = 1100 ft

We have

           Depth fallen = Average rate of lowering per​ minute x Time gap

           1100 = Average rate of lowering per​ minute x 30

           Average rate of lowering per​ minute = 36.67 ft/min

7 0
3 years ago
-3k + 3(k - 6) = 18<br> Help please!!!
vovangra [49]
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4 0
3 years ago
Suppose x=10 and y=10. what is x after evaluating the expression (y&gt;= 10)||(x++ &gt;10)? java
Mamont248 [21]
<span>Suppose x=10 and y=10. what is x after evaluating the expression (y>= 10)||(x++ >10)? java
Answer is 10</span>
4 0
3 years ago
Amy plays a game with an ordinary, fair dice.
rjkz [21]

Answer:

Ok so I’m stuck with this question too But I got the top part.

p=1/6

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8 0
3 years ago
Find the average value of f over region
SVETLANKA909090 [29]
D is a right triangle with base length 1 and height 8, so the area of D is \dfrac12(1)(8)=4.

The average value of f(x,y) over D is given by the ratio

\dfrac{\displaystyle\iint_Df(x,y)\,\mathrm dA}{\displaystyle\iint_D\mathrm dA}

The denominator is just the area of D, which we already know. The average value is then simplified to

\displaystyle\frac74\iint_Dxy\,\mathrm dA

In the x,y-plane, we can describe the region D as all points (x,y) that lie between the lines y=0 and y=8x (the lines which coincide with the triangle's base and hypotenuse, respectively), taking 0\le x\le1. So, the integral is given by, and evaluates to,

\displaystyle\frac74\int_{x=0}^{x=1}\int_{y=0}^{y=8x}xy\,\mathrm dy\,\mathrm dx=\frac78\int_{x=0}^{x=1}xy^2\bigg|_{y=0}^{y=8x}\,\mathrm dx
=\displaystyle56\int_{x=0}^{x=1}x^3\,\mathrm dx
=14x^4\bigg|_{x=0}^{x=1}
=14
3 0
3 years ago
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