Question

Please help!! I need the answer to the question in the picture!!!!

Answer 1

Answer:

$\large\boxed{D.\ x=-2(y+3)^2-1}$

Step-by-step explanation:

The equation of a horizontal parabola in the standard form:

$x=a(y-k)^2+h$

(h, k) - vertex

if a > 0, then open right

if a < 0, then open left

We have the vertrex (-1, -3) and the parabola is open left (a < 0).

Therefore the equation of a given parabola could be:

$x=-2(y-(-3))^2+(-1)=-2(y+3)^2-1$