If a letter is chosen at random from the word MATHEMATICS, what is the probability of choosing a T? A. 1/11 B. 2/11 C. 4/11 D. 5
1 answer:
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Answer:
a. 24
b. 864
Step-by-step explanation:
a. The demand function is:
P = 60 - 2Q
When P = 12:
12 = 60 - 2Q
2Q = 60 - 12
2Q = 48
Q = 48/2 = 24
b. Consumer surplus is given as the integral of Demand function:
This implies that:
Answer:
No, we can't reject the dealer's claim with a significance level of 0.05.
Step-by-step explanation:
We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.
You take a random sample of 600 cars in San Francisco and find that 141 are blue.
<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>
SO, Null Hypothesis, : p = 25% {means that 25% of all cars in San Francisco are blue}
Alternate Hypothesis, : p
25% {means that % of all cars in San Francisco who are blue is different from 25%}
The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;
T.S. = ~ N(0,1)
where, = sample proportion of 600 cars in San Francisco who are blue =
= 0.235
n = sample of cars = 600
So, <u><em>test statistics</em></u> =
= -0.866
<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>
Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.
Answer:
Step-by-step explanation:
On a single roll of a pair of dice. When a pair of dice are rolled the possible outcomes are as follows:
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
The number of outcomes that gives us 12 are (6,6). There is only one outcome that gives us sum 12.
Total outcomes = 36
Odd against favor =
Number of outcomes of getting sum 12 is 1
Number of outcomes of not getting sum 12 is 36-1= 35
odds against rolling a sum of 12=