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shtirl [24]
3 years ago
10

Need help with this math question

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
3 0

Answer:

23%

Step-by-step explanation:

There are 4 male and 3 female freshmen. Thus the total number of freshmen is 7.

On the other hand, we have 14 male students and 16 female students. Thus the total number of students is 30.

If a student is selected at random, the probability that the student is a freshman is;

( 7/30) * 100 = 23.33%

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A water yank holds 18,000 gallons. How long will it take for the water level to reach 6,000 gallons if the water is used at an a
Oduvanchick [21]

Answer:

see below  PLEASE GIVE BRAINLIEST

Step-by-step explanation:

18,000 - 6000 = 12,000

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2 years ago
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8 0
2 years ago
The function g(x)=x^2+3. The f(x)=g(x+2)
vekshin1

Answer:

f(x)=x^2+6x+12

Step-by-step explanation:

Given:

The function 'g(x)' is given as:

g(x)=x^2+3

Now, the function 'f(x)' is given as:

f(x)=g(x+2)

So, the function 'f(x)' is a transformation of 'g(x)'.

In order to find f(x), we replace 'x' by (x + 2) in the 'g(x)' function equation. This gives,

g(x+2)=(x+2)^2+3

Using the identity (a+b)^2=a^2+b^2+2ab, we get:

g(x+2)=x^2+3^2+6x+3\\\\g(x+2)=x^2+9+6x+3\\\\g(x+2)=x^2+6x+12

Hence the function f(x) is given as:

f(x)=x^2+6x+12

4 0
3 years ago
What is a three digit number thats an odd multiple of three and the product of its digits is 24 and is larger than 15 squared?
Reika [66]
The only way 3 digits can have product 24 is 
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4 
To be divisible by 3 the sum of the digits must be divisible by 3.
1+  3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3. 

So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.

Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.

The others must end in 3. 

They must be greater than 152 which is 225. So the

First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.

The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.  
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
7 0
3 years ago
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