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shtirl [24]
4 years ago
10

Need help with this math question

Mathematics
1 answer:
Y_Kistochka [10]4 years ago
3 0

Answer:

23%

Step-by-step explanation:

There are 4 male and 3 female freshmen. Thus the total number of freshmen is 7.

On the other hand, we have 14 male students and 16 female students. Thus the total number of students is 30.

If a student is selected at random, the probability that the student is a freshman is;

( 7/30) * 100 = 23.33%

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-15=-11x+18 solve for x​
Mademuasel [1]

Answer:

-3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
HELP ME
zhuklara [117]

Answer:

$127.60

Step-by-step explanation:

If Lisa bought 30 shares of stock at $54.02 per share, total cost price will be:

30×$54.02

= $1620.6

If she then sold her shares at $58.19 per share, her total selling price will be:

30×$58.19

= $1745.7

Profit = selling price - cost price

Profit = $1745.7-$1620.6

Profit = $125.1

If her broker charges a 2% commission for all transactions, her total charge will be:

2% of $125.1

= $2.50

Her net gain = profit + broker's charge

= $125.1+$2.50

= $127.60

7 0
3 years ago
The area of a rectangular painting is 8613 cm?.
andreyandreev [35.5K]

Answer:

The width is 87 cm

Step-by-step explanation:

The area of a rectangle is given by

A = l*w

8613 = 99 * w

Divide each side by 99

8613 / 99 = 99 w /99

87 = w

The width is 87 cm

3 0
3 years ago
Read 2 more answers
Determine whether the given system has a unique solution, no solution, or infinitely many solutions.
victus00 [196]

Answer:

The system has no solution.

Step-by-step explanation:

To find the solution to this system of linear equations

\left\begin{array}{ccccc}-3x_1&+x_2&-2x_3&=&8&\\x_1&+5x_2&-x_3&=&4&\\-x_1&+11x_2&-4x_3&=&1&\end{array}\right

First, state the problem in matrix form, this means, extracting only the numbers, and putting them in a box.

\left[ \begin{array}{ccc|c} -3 & 1 & -2 & 8 \\\\ 1 & 5 & -3 & 4 \\\\ -1 & 11 & -4 & 1 \end{array} \right]

This is called an augmented matrix. The word “augmented” refers to the vertical line, which we draw to remind ourselves where the equals sign belong

Next, transform the augmented matrix to the reduced row echelon form with the help of Row Operations.

Row Operation 1: multiply the 1st row by -1/3

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 1 & 5 & -1 & 4 \\\\ -1 & 11 & -4 & 1 \end{array} \right]

Row Operation 2: add -1 times the 1st row to the 2nd row

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & \frac{16}{3} & - \frac{5}{3} & \frac{20}{3} \\\\ -1 & 11 & -4 & 1 \end{array} \right]

Row Operation 3: add 1 times the 1st row to the 3rd row

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & \frac{16}{3} & - \frac{5}{3} & \frac{20}{3} \\\\ 0 & \frac{32}{3} & - \frac{10}{3} & - \frac{5}{3} \end{array} \right]

Row Operation 4: multiply the 2nd row by 3/16

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & -15 \end{array} \right]

Row Operation 5: add -32/3 times the 2nd row to the 3rd row

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & -15 \end{array} \right]

Row Operation 6: multiply the 3rd row by -1/15

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & 1 \end{array} \right]

Row Operation 7: add -5/4 times the 3rd row to the 2nd row

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

Row Operation 8: add 8/3 times the 3rd row to the 1st row

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

Row Operation 9: add 1/3 times the 2nd row to the 1st row

\left[ \begin{array}{cccc} 1 & 0 & \frac{9}{16} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & \frac{9}{16} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

which corresponds to the system

\left\begin{array}{ccccc}x_1&&+\frac{9}{16} x_3&=&0&\\&1x_2&-\frac{5}{16}x_3&=&0&\\&&0&=&1&\end{array}\right

Equation 3 cannot be solved, therefore, the system has no solution.

7 0
4 years ago
Please help asap, will give brainiest. TY! :3
lilavasa [31]

Answer:

Page 1::1 & 3 & 4

Page 2:6

Page 3:8/1

Page 4:15 3/4

Step-by-step explanation:

HOPE THIS HELPS!!

8 0
3 years ago
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